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Ilya [14]
2 years ago
8

P(A)* P(B)≠ p(AnB) Why does it contain a not equal to sign

Mathematics
2 answers:
kramer2 years ago
5 0

Answer:

P(A) * P(B)

p(a+b)

P(a+b) is not equal to p( AnB)

Hope this helps plz hit the crown :D

RoseWind [281]2 years ago
4 0

Answer:

P(A|D) and P(D|A) from the table above are not equal because P(A|D) =  and P(D|A) =

Step-by-step explanation:

Conditional probability is the probability of one event occurring  with some relationship to one or more other events

.

P(A|D) is called the "Conditional Probability" of A given D

P(D|A) is called the "Conditional Probability" of D given A

The formula for conditional probability of P(A|D) = P(D∩A)/P(D)

The formula for conditional probability of P(D|A) = P(A∩D)/P(A)

The table

              ↓         ↓       ↓

           :  C     :   D    : Total

→ A      :  6     :    2    :   8

→ B      :  1      :    8    :   9

→Total :  7     :    10  :  17

∵ P(A|D) = P(D∩A)/P(D)

∵ P(D∩A) = 2 ⇒ the common of D and A

- P(D) means total of column D

∵ P(D) = 10

∴ P(A|D) =

∵ P(D|A) = P(A∩D)/P(A)

∵ P(A∩D) = 2 ⇒ the common of A and D

- P(A) means total of row A

∵ P(A) = 8

∴ P(D|A) =

∵ P(A|D) =

∵ P(D|A) =

∵   ≠  

∴ P(A|D) and P(D|A) from the table above are not equal

Step-by-step explanation:

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Given

p(x) = \frac{x^2-2x-3}{x+2} -- Missing from the question

Required

The behavior of the function around its vertical asymptote at x = -2

p(x) = \frac{x^2-2x-3}{x+2}

Expand the numerator

p(x) = \frac{x^2 + x -3x - 3}{x+2}

Factorize

p(x) = \frac{x(x + 1) -3(x + 1)}{x+2}

Factor out x + 1

p(x) = \frac{(x -3)(x + 1)}{x+2}

We test the function using values close to -2 (one value will be less than -2 while the other will be greater than -2)

We are only interested in the sign of the result

----------------------------------------------------------------------------------------------------------

As x approaches -2 implies that:

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