Present value of annuity PV = P(1 - (1 + r/t)^-nt) / (r/t)
where: p is the monthly payment, r is the APR = 14.12% = 0.1412, t is the number of payments in one year = 12, n is the number of years = 2.
1,120.87 = P(1 - (1 + 0.1412/12)^(-2 x 12)) / (0.1412 / 12)
0.1412(1120.87) = 12P(1 - (1 + 0.1412/12)^-24)
P = 0.1412(1120.87) / 12(1 - (1 + 0.1412/12)^-24) = $53.88
Minimum monthly payment = 3.15% of 1120.87(1 + 0.1412/12) = 0.0315 x 1120.87(1 + 0.1412/12) = $35.72
Therefore, his first payment will be greater than the minimum payment by 53.88 - 35.72 = $18.16
Answer:
5x^2−10x−2
Step-by-step explanation:
I hope this is what you are looking for I just added (5x^2 – 9) + (-10x + 7)
2x - 5x + 4 = 0
- 3x = - 4
x = 4/3
Answer:
boom
Step-by-step explanation:
Answer:
and as 
Step-by-step explanation:
Given
-- Missing from the question
Required
The behavior of the function around its vertical asymptote at 

Expand the numerator

Factorize

Factor out x + 1

We test the function using values close to -2 (one value will be less than -2 while the other will be greater than -2)
We are only interested in the sign of the result
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As x approaches -2 implies that:
Say x = -3


We have a negative value (-12); This will be called negative infinity
This implies that as x approaches -2, p(x) approaches negative infinity

Take note of the superscript of 2 (this implies that, we approach 2 from a value less than 2)
As x leaves -2 implies that: 
Say x = -2.1

We have a negative value (-56.1); This will be called negative infinity
This implies that as x leaves -2, p(x) approaches negative infinity

So, the behavior is:
and as 