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matrenka [14]
3 years ago
10

Rectangle JKLM is rotated 90° clockwise about the origin.

Mathematics
1 answer:
shusha [124]3 years ago
4 0

Answer:

Clockwise rotation 90 ° about origin

R_{90, clockwise, origin}(x,y) -> (y,-x)

J(-4,1) therefore

R_{90, clockwise, origin}J(-4,1) -> J'(1,+4)  this answer was form other person credits to him/her

Step-by-step explanation:

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3 years ago
Identify the linear function graph
crimeas [40]

The answer is choice B in the upper right hand corner.

Choice B is the graph that is a straight line and it's a single unbroken straight line. There are no gaps or jumps or any kinds of bends like choice A shows. Choice A is an absolute value graph, which is the result of gluing together two linear functions. Overall, graph A is considered nonlinear. Choices C and D are nonlinear as well.

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3 years ago
HELP. PLEASE
tatuchka [14]
If we calculate the distance between two points, it is equivalent to one side of the rectangle. Using the distance formula:
d = √((x₂ - x₁)² + (y₂-y₁)²)
We compute the distance between the points (-3,2) and (5,4)
d = √((5 + 3)² + (4 - 2)²) = √68
Now, we check the next two points:
d = √((6 - 5)² + (0 - 4)² = √17
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P = 2(l₁ + l₂)
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8 0
3 years ago
Find the magnitude of the vector from the origin to (8. - 6) and write the vector as the sum of unit vectors.
Kay [80]

The magnitude of the vector from the origin is 10

The unit vector in of the vector from the origin as   (8/10, -6/10

<u>Step-by-step explanation:</u>

<u>1.Finding the magnitude,</u>

we have the formula,

magnitude=√a²+b²

we have the values as a=8 and b=-6

Finding the magnitude we get,

magnitude=√a²+b²

magnitude=√8²+6²

magnitude=√100

magnitude=10

The magnitude of the vector from the origin is 10

<u>2.Finding the  unit vector</u>

Divide by the magnitude

Unit vector: (8/10, -6/10)

The unit vector in of the vector from the origin as   (8/10, -6/10

3 0
2 years ago
At the bright-as-day light bulb factory, 5 out of each 136 bulbs produced are defective. If the daily production is 2720 bulbs,
lions [1.4K]

Answer:

100 lightbulbs

Step-by-step explanation:

Basically find the percentage of lightbulbs that are bad. 5/136. So about 3. 6 percent. I'm going to use a more exact form of this percent for my calculations though. Now use the decimal for of this (0.036....) and multiply it by 2720. Using my exact decimal, the answer just so happened to be exactly 100. So there will be 100 defective lightbulbs per day. (Teachers are a stickler for units, so don't forget them if it's for a teacher)

Hope this helps!

4 0
2 years ago
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