Ask question

Ask question

All categories

Dmitry_Shevchenko [17]

3 years ago

7

A truck fuel can hold 44 gallons of gasoline. If 6.78 gallons of gasoline are in the tank how many more gallons are needed to fi

ll the tank

2 answers:

SSSSS [86.1K]3 years ago

7 0

Answer: 38.22

Step-by-step explanation:

disa [49]3 years ago

7 0

Answer:

37.22

Step-by-step explanation:

44 - 6.78= 37.22

You might be interested in

In a certain year the price of gasoline rose by 20% during January, fell by 20% during February, rose by 25% in March, and fell

zavuch27 [327]

Answer:

Fell by 25%

Step-by-step explanation:

+20% January

-20% February (20-20 is zero, so we're back to the original price we started at here)

+25% March

?? April

Currently, we are 25% more than what we had, so to get back to normal, the price needs to go down by 25 percent. This will put us back to zero. Put another way...

+20%-20%+25%-25%=0% (Original Price)

8 0

3 years ago

Is 95,590,956 divisible by 9

Ad libitum [116K]

Answer:

10621217.333

Step-by-step explanation:

4 0

3 years ago

Read 2 more answers

{This question has been deleted}

stiks02 [169]

Answer:

this question isn't deleted yet

4 0

3 years ago

Read 2 more answers

What is the Area of a triangle with the height of 0.7 cm and a base of 6cm

Mashcka [7]

Answer: Area = 2.1 $cm^{2}$

Step-by-step explanation:

4 0

3 years ago

From 1995-2005, the hourly pay for lifeguards at an outdoor swimming pool increased by 2% per year. The hourly pay, P(t), in dol

12345 [234]

Answer:

The hourly pay for the lifeguards in 2001 was of $6.31.

Step-by-step explanation:

The hourly pay, in dollars, in t years after 1995, is given by the following equation:

$P(t) = 5.60(1.02)^{t}$

What was the hourly pay for the lifeguards in 2,001?

2001 is 2001 - 1995 = 6 years after 1995. So this is P(6).

$P(t) = 5.60(1.02)^{t}$

$P(6) = 5.60(1.02)^{6} = 6.31$

The hourly pay for the lifeguards in 2001 was of $6.31.

7 0

3 years ago