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Semenov [28]
4 years ago
10

Do all cloned plants have the same genetic makeup? why?

Chemistry
1 answer:
Yuki888 [10]4 years ago
8 0
Cloned material have the same genetic make up because they are formed after one egg cell is fertilized but spilts to form embryos.
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Is tap water a heterogeneous or homogenous mixture? Explain your answer.
Tomtit [17]
A homogeneous mixture has the same uniform appearance and composition throughout. A heterogeneous mixture consists of visibly different substances or phases. Homogeneous mixtures

So the answer is heterogeneous.
3 0
4 years ago
How does extinction affect evolution?
Luden [163]
It slows down evolution
8 0
3 years ago
At standard temperature and pressure, the element with the chemical symbol _______ is a liquid.
Bezzdna [24]

The only liquid elements at standard temperature and pressure are bromine (Br) and mercury (Hg). Although, elements caesium (Cs), rubidium (Rb), Francium (Fr) and Gallium (Ga) become liquid at or just above room temperature.

5 0
4 years ago
1.674×10-4 mol of an unidentified gaseous substance effuses through a tiny hole in 86.6 s. Under identical conditions, 1.715×10-
siniylev [52]
<h2>Answer:</h2>

44.06 g/mol

<h3>Explanation:</h3>

We are given;

  • Number of moles of unidentified gas as 1.674×10^-4 mol
  • Time of effusion of unidentified gas 86.6 s
  • Number of moles of Argon gas as 1.715×10^-4 mol
  • Time of effusion of Argon gas is 84.5 s

We are supposed to calculate the molar mass of unidentified gas

<h3>Step 1: Calculate the effusion rates of each gas</h3>

Effusion rate = Number of moles/time

Effusion rate of unidentified gas (R₁)

 =  1.674×10^-4 mol ÷ 86.6 s

 = 1.933 × 10^-6 mol/s

Effusion rate of Argon gas (R₂)

 = 1.715×10^-4 mol ÷ 84.5 sec

= 2.030 × 10^-6 mol/s

<h3>Step 2: Calculate the molar mass of unidentified gas</h3>
  • Assuming the molar mass of unidentified gas is x;
  • We can use the Graham's law of effusion to find x;
  • According to Graham's law of diffusion;

\frac{R_{1}}{R_{2}}}=\frac{\sqrt{MM_{Ar}}}{\sqrt{X}}

But, Molar mass of Argon is 39.948 g/mol

Therefore;

\frac{1.933*10^-6mol/s}{2.030*10^-6mol/s}}=\frac{\sqrt{39.948}}{\sqrt{X}}

0.9522=\frac{\sqrt{39.948}}{\sqrt{X}}

Solving for X

x = 44.06 g/mol

Therefore, the molar mass of the identified gas is 44.06 g/mol

3 0
4 years ago
Sue has to find the empirical formula of a compound containing 81.8 grams of carbon and 18.2 grams of hydrogen in 100 grams of c
ArbitrLikvidat [17]
She would divide that mass of each element by it molar mass the answer is C <span />
6 0
3 years ago
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