Y=mx+b where m=slope=(dy/dx) and b=y-intercept (value of y when x=0)
You have two points...(1,-2),(3,2) so
m=(y2-y1)/(x2-x1)=(2--2)/(3-1)
m=4/2=2 now that you have the slope...
y=2x+b, you can use either point to solve for the y-intercept, I'll use (3,2)
2=2(3)+b
2=6+b
b=-4 so the line is:
y=2x-4
Let r(cos O + i sin O) be a cube root of 125(cos 288 + i sin 288)
then
r^3(cos O + i sin O)^3 = 125(cos 288 + i sin 28)
so r^3 = 125 and cos 3O + i sin 3O = cos 288 + i sin 288
so r = 5 and 3O = 288 + 360p and O = 96 + 120p
so one cube root is 5 (cos 96 + i sin 96)
Im a little rusty at this stuff Its been a long time.
Im not sure of the other 2 roots
sorry cant help you any more
Answer:
Sorry this is late and I think this is right.
They are both parallel, they have the same slope, and do <em>not </em>intersect. If you were to draw a slope out for it, you would find this to be true.
For example: Say the question called for you to explain why there aren't any solutions to these system of inequalities:
<em>y < - 1/2x -3</em>
<em>y > 1/2x + 2</em>
<em>y= -x/2 -3</em> and <em>y= -x/2 + 2 </em>have the same exact slope, are parallel, and never intersect. The first line is 5 units below the second line when x = 0. Because the lines are parallel, it is always below the second line. The solutions of y < - x/2 -3 are the points in the plane below the first line. The solutions of y > 1/2 + 2 are points above the second line.
I hope this helps you. Good luck on whatever you're working on and stay safe! Please let me know if this helped you or didn't.
Answer: A. Wed to Fri
We have a bunch of natural numbers and we're told a pair is in the ratio 2:5.
For natural numbers to have this ratio, the left number will be a multiple of two and the right number will be a multiple of five.
Our only option for a multiple of 5 is 15, Friday. So we have
2:5 = x:15
and x = 15*2/5 = 6
which was Wednesday's number. So we get Wed:Fri=6:15=2:5.
