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2 years ago

Which of the following representations are functions?

Mathematics

1 answer:

allsm [11]2 years ago

4 0

Answer: A and B only

Step-by-step explanation:

In function, for one value of x there must be only one value of y.

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Solve the inequality-7x>21.what is the graph of the solution?

uranmaximum [27]

-7x>21
divide both sides by -7

7 0

2 years ago

Find the measure of angle b.

nika2105 [10]

Answer:

47°

Step-by-step explanation:

vertical angles are congruent

3 0

2 years ago

3x -4y= -20 -x +2y =10 whats the value of y

Anni [7]

3x-4y=10
-20-x+2y=10 then -30+2y=x now plug this in the other equation:
3(-30+2y)-4y=10
-90+6y-4y=10
2y=100
y=50

4 0

2 years ago

the value of c guaranteed to exist by the Mean Value Theorem for V(x) = x² in the interval [0, 3] is...? a) 1 b) 2 c) 3/2 d) 1/2

lilavasa [31]

Answer: c) $\dfrac{3}{2}$ .

Step-by-step explanation:

Mean value theorem : If f(x) is defined and continuous on the interval [a,b] and differentiable on (a,b), then there is at least one number c in the interval (a,b) (that is a < c < b) such that

$\begin{displaymath}f'(c) = \frac{f(b) - f(a)}{b-a} \cdot\end{displaymath}$

Given function : $f(x) = x^2$

Interval : [0,3]

Then, by the mean value theorem, there is at least one number c in the interval (0,3) such that

$f'(c)=\dfrac{f(3)-f(0)}{3-0}\\\\=\dfrac{3^2-0^2}{3}=\dfrac{9}{3}\\\\=3$

$\Rightarrow\ f'(c)=3\ \ \ ...(i)$

Since $f'(x)=2x$

then, at x=c, $f'(c)=2c\ \ \ ...(ii)$

From (i) and (ii), we have

$2c=3\\\\\Rightarrow\ c=\dfrac{3}{2}$

Hence, the correct option is c) $\dfrac{3}{2}$ .

4 0

3 years ago

The table shows the total cost, y, for renting a playroom for a party with x party guests.

tatyana61 [14]

Answer:

y = 9x + 175

Step-by-step explanation:

Choose one value for y in the table, for example, 211. All the equations have 9x, so multiply the corresponding x for 9:

9•4 = 36

Now make the value of y - 36:

211 - 36 = 175

Now you have the equation:

y = 9x +175

6 0

2 years ago