Someone please help??

Mathematics

1 answer:

ivolga24 [154]3 years ago

3 0

(B) is your answer for sure is what i would say

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You are mowing a lawn. After 12 minutes, 52% of the lawn still needs mowed. How long does it take to mow the entire lawn? Write

aleksley [76]

12/x = 52/48
12 * 48 = 52x
x = 11.07 This is one way to do it.

Let the time = x
Let the part of the lawn = y

The general equation
y = k*x
52/100 = k * 12
k = 0.043333
y = 0.043333*x
y = 0.043333* 11.08
y = 0.48 which is what it should be.

Yet another way is to let y = kx
52 = k*12
k = 52/12
k = 4.33333333

y = 4.333333 * x
y = 4.333333 * 48
48 = 4.333333 * x
x = 11.07 which is just what you should expect.

7 0

2 years ago

Find d for the arithmetic series with S17=-170 and a1=2

Irina18 [472]

So, we know the sum of the first 17 terms is -170, thus S₁₇ = -170, and we also know the first term is 2, well

$\bf \textit{ sum of a finite arithmetic sequence}\\\\
S_n=\cfrac{n(a_1+a_n)}{2}\qquad 
\begin{cases}
n=n^{th}\ term\\
a_1=\textit{first term's value}\\
----------\\
n=17\\
S_{17}=-170\\
a_1=2
\end{cases}
\\\\\\
-170=\cfrac{17(2+a_{17})}{2}\implies \cfrac{-170}{17}=\cfrac{(2+a_{17})}{2}
\\\\\\
-10=\cfrac{(2+a_{17})}{2}\implies -20=2+a_{17}\implies -22=a_{17}$

well, since the 17th term is that much, let's check what "d" is then anyway,

$\bf n^{th}\textit{ term of an arithmetic sequence}\\\\
a_n=a_1+(n-1)d\qquad 
\begin{cases}
n=n^{th}\ term\\
a_1=\textit{first term's value}\\
d=\textit{common difference}\\
----------\\
n=17\\
a_{17}=-22\\
a_1=2
\end{cases}
\\\\\\
-22=2+(17-1)d\implies -22=2+16d\implies -24=16d
\\\\\\
\cfrac{-24}{16}=d\implies -\cfrac{3}{2}=d$

6 0

3 years ago

3. What value of makes a true equivalent fraction statement.<br> 5 30<br> 54<br> C

VashaNatasha [74]

Answer:

$x$ = 9