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Romashka-Z-Leto [24]
3 years ago
12

A container of beads contains: 8 red beads, 6 yellow beads, and 6 green beads. A bead will be drawn from the basket and replaced

60 times. What is the reasonable prediction for the number of times the green or red bead is drawn? PLEASE ANSWER AS SOON AS YOU CAN.
Mathematics
1 answer:
77julia77 [94]3 years ago
7 0

Answer:

Because of probability, a green or red bead would be drawn 14/20 times because there are 20 total beads and adding together the numbers for green and red. From this, if you multiply by 3/3 you can see that 42/60 times it will be a green bead. A reasonable prediction for green beads would then be 42 times. Hope it helps :D

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Read 2 more answers
Suppose that the probability of a baseball player getting a hit in an at-bat is 0.3089. If the player has 25 at-bats during a we
klio [65]

Answer:

P(X>9) = 0.3593

Step-by-step explanation:

Previous concepts  

The binomial distribution is a "DISCRETE probability distribution that summarizes the probability that a value will take one of two independent values under a given set of parameters. The assumptions for the binomial distribution are that there is only one outcome for each trial, each trial has the same probability of success, and each trial is mutually exclusive, or independent of each other".  

Solution to the problem

Let X the random variable of interest, on this case we now that:

X \sim Binom(n=25, p=0.3089)  

The probability mass function for the Binomial distribution is given as:  

P(X)=(nCx)(p)^x (1-p)^{n-x}  

For this case we want this probability:

P(X >9)

And we can use the complement rule like this:

P(X>9) = 1-P(X \leq 8)= 1-[P(X=0) + P(X=1) +....+P(X=8)]And we can find the individual probabilities like this:

P(X=0) =(25C0)(0.3089)^0 (1-0.3089)^{25-0} =0.0000974  

P(X=1) =(25C1)(0.3089)^1 (1-0.3089)^{25-1} =0.0011  

P(X=2) =(25C2)(0.3089)^2 (1-0.3089)^{25-2}=0.00584  

P(X=3) =(25C3)(0.3089)^3 (1-0.3089)^{25-3}= 0.02  

P(X=4) =(25C4)(0.3089)^4 (1-0.3089)^{25-4}=0.049  

P(X=5) =(25C5)(0.3089)^5 (1-0.3089)^{25-5}=0.092  

P(X=6)=(25C6) (0.3089)^6 (1-0.3089)^{25-6} = 0.138

P(X=7) =(25C7)(0.3089)^7 (1-0.3089)^{25-7}=0.167

P(X=8) =(25C8)(0.3089)^8 (1-0.3089)^{25-8}=0.168

And in order to do the operations we can use the following excel code:

"=1-BINOM.DIST(8,25,0.3089,TRUE)"  

And we got:

P(X>9) = 0.3593

4 0
3 years ago
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