It's a probability problem to find the odds of picking a green or red
shirt out of the 10 shirts on Thursday, Friday and Saturday since you
have randomly already know you have picked a blue shirt on the other
days. Not sure if you have this as a multiple question problem as you didn't list any possible answers (A. 7/20, B. 5/47, C. 2/5, D. 4/125) to the question. A, B, C, D being like 7 chances out of 20, 5 chances out 47, 2 chances out of chances 5 or 4 chances out of 125 (example answers only).
Probability = Number favorable outcomes / total number of outcomes
Answer:
(4,4)
Step-by-step explanation:
y = 2x - 4 -------eqn 1
4y = x + 12 ------eqn 2
From eqn 1 y = 2x - 4; insert in eqn 2
4 (2x-4) = x + 12 (open the bracket)
8x - 16 = x + 12 (taking like figures to the same side, sign changes)
8x - x = 12 + 16
7x = 28
x = 28/7
x = 4
From eqn 1
y = 2x - 4
y = 2(4) - 4
y = 8 - 4
y = 4
(x,y) = (4,4)
Answer:
x = -3 or x = 3
Step-by-step explanation:
Subtract 9 from both sides.
x^2 - 9 = 0
Factor the left side. There is no common factor of the terms. It is a binomial which is the difference of two squares, so it factors into the product of a sum and a difference.
(x + 3)(x - 3) = 0
Set each factor equal to zero.
x + 3 = 0 or x - 3 = 0
Solve each equation.
x = -3 or x = 3
Answer:
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Step-by-step explanation:
55% of the tables would be 33 tables times 10 chairs equals 330 Chairs That mean 60 Tables -33 tables Leaves you with 27 tables Times 8 Chairs Equals 216 Chairs So 330 and 216Equals 546 chairs
-13 becomes +13. 0 stays 0. 13 + 0 is 13, which is your answer.
