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Sloan [31]
3 years ago
5

Solve w^2+13w+42=0 by factoring.

Mathematics
2 answers:
Bingel [31]3 years ago
4 0
Move all terms to the left side and set equal to zero. Then set each factor equal to zero.
w = -6, -7
Hope this helps! :)
andre [41]3 years ago
3 0
The answer is therefore (w+7)(w+6), meaning the zeros are -7 and -6
Hope this helps

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Find the surface area of the figure below.
gayaneshka [121]

Answer:

261 cm²

Step-by-step explanation:

To find the surface area of a square pyramid, you must first recognize all of the shapes.

There are four triangles and one square.

  • To find the area of a square, multiply the side by itself twice.
  • To find the area of a triangle, multiply the base and the height, then multiply the product by 1/2.

The triangles have a base of 9 and a height of 10.

9*10=90

Multiply the product by 1/2.

90*1/2 = 45

There are four triangles.

45*4=180

The area of all three triangles is 180 centimeters; the area of a single triangle is 45 centimeters.

There square has sides of 9 centimeters.

9*9=81

The area of the square is 81 centimeters.

Lastly, we add the areas of the shapes.

45+45+45+45+81 = 261.

Therefore, the surface area of this square prism is 261 cm².

You can use this layout to find the surface area of a square pyramid.

6 0
3 years ago
Solve please This is Composite Figures :)
Ksivusya [100]
The area is that of two 20 yd squares and one 20 yd circle.
.. A = 2*(20 yd)^2 +(π/4)*(20 yd)^2
.. = (2 +π/4)*(400 yd^2)
.. = (800 +100π) yd^2
.. ≈ 1114.16 yd^2

The perimeter is that of a 20 yd circle and 80 yd more.
.. P = π*20 yd + 80 yd
.. ≈ 142.83 yd
7 0
3 years ago
How to write 32,005,008 in expanded form?
Anna [14]
32,005,008 = 30,000,000 + 2,000,000 + 5,000 + 8
4 0
3 years ago
In ADEF, the measure of
MrMuchimi

Answer:

X= 51.71

You can use a protractor

6 0
3 years ago
I need help writing the first 5 terms of the sequence!
Angelina_Jolie [31]

The first five terms of the sequence are 1, 4, 7, 10, 13.

Solution:

Given data:

a_{1}=1

a_{n}=a_{n-1}+3

General term of the arithmetic sequence.

a_{n}=a_{n-1}+d, where d is the common difference.

d = 3

a_{n}=a_{n-1}+3

Put n = 2 in a_{n}=a_{n-1}+3, we get

a_{2}=a_1+3

a_{2}=1+3

a_2=4

Put n = 3 in a_{n}=a_{n-1}+3, we get

a_{3}=a_2+3

a_{3}=4+3

a_3=7

Put n = 4 in a_{n}=a_{n-1}+3, we get

a_{4}=a_3+3

a_{4}=7+3

a_4=10

Put n = 5 in a_{n}=a_{n-1}+3, we get

a_{5}=a_4+3

a_{5}=10+3

a_5=13

The first five terms of the sequence are 1, 4, 7, 10, 13.

3 0
4 years ago
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