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ycow [4]
3 years ago
6

What is 139.5 as a fraction?

Mathematics
1 answer:
Zina [86]3 years ago
5 0

Answer:

139.5/1 or 1395/10

Step-by-step explanation:

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Answer:

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• x(t) = 6t --- equation (a)

• y(t) = 3t - 2 --- equation (b)

→ From equation (a), make t the subject:

→ \: { \tt{x(t) = 6t }} \\  \\ → \: { \tt{t =  \frac{x(t)}{6} }}

• substitute for t in equation (b)

→ \: { \tt{y(t) =  3(\frac{x(t)}{6}) - 2 }} \\  \\ → \: { \tt{y(t) =  \frac{x(t)}{2} - 2 }}

• Assume t is 1:

→ \: { \tt{y =  \frac{x}{2}  - 2}} \\  \\ → \: { \boxed{ \tt{2y = x - 4}}}

• when x is zero, y is -4

→ \: { \tt{2y = 0 - 4 =  - 4}} \\

• when x is 6, y is 1

→ \: { \tt{2y = 6 - 4 = 2 }} \\ { \tt{y = 1}}

8 0
2 years ago
(1 point) For each of the indefinite integrals below, choose which of the following substitutions would be most helpful in evalu
PIT_PIT [208]

Answer:

1- optionC X= 6secθ

2- option B. X= 6sin(θ)

3- option A. X= 6tan(θ)

4- option C. X= 6sec(θ)

5- option A. X= 6tan(θ)

Step-by-step explanation:

Attached is the full question

5 0
3 years ago
A triangle has coordinates A (1, 5), B (-2, 1) and C (0, -4). What are the new coordinates if the triangle is dilated with a sca
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IF you are dilating about the origin, which you didn't exactly state, the new coordinates are A' (1/5, 1), B' (2/5, 1/5), C' (0, 4/5).  Dilation is all about distance, so you have to move the new coordinates to whatever the scale factor is times the x and y distance.  For example, A is at (1, 5), so 1/5 of 1 is 1/5, and 1/5 of 5 is 1, hence your new coordinate for A.  It is a fifth of the distance from the origin as its preimage is.
8 0
3 years ago
How do you say 1.75 in words
gizmo_the_mogwai [7]
You would say one and seventy-five hundredths
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3 years ago
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Prepare the journal entry to record the issuance of 5,000 shares of $20 par common stock for $25 per share
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Answer:

value preferred stock for $65,250 cash

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