Answer:
<u>Answer</u><u>:</u><u> </u><u>(</u><u>0</u><u>,</u><u> </u><u>-</u><u>4</u><u>)</u><u> </u><u>and</u><u> </u><u>(</u><u>6</u><u>,</u><u> </u><u>1</u><u>)</u>
• x(t) = 6t --- equation (a)
• y(t) = 3t - 2 --- equation (b)
→ From equation (a), make t the subject:

• substitute for t in equation (b)

• Assume t is 1:

• when x is zero, y is -4

• when x is 6, y is 1

Answer:
1- optionC X= 6secθ
2- option B. X= 6sin(θ)
3- option A. X= 6tan(θ)
4- option C. X= 6sec(θ)
5- option A. X= 6tan(θ)
Step-by-step explanation:
Attached is the full question
IF you are dilating about the origin, which you didn't exactly state, the new coordinates are A' (1/5, 1), B' (2/5, 1/5), C' (0, 4/5). Dilation is all about distance, so you have to move the new coordinates to whatever the scale factor is times the x and y distance. For example, A is at (1, 5), so 1/5 of 1 is 1/5, and 1/5 of 5 is 1, hence your new coordinate for A. It is a fifth of the distance from the origin as its preimage is.
You would say one and seventy-five hundredths
Answer:
value preferred stock for $65,250 cash
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