Answer:
Continuously
Step-by-step explanation:
Compounded continuously:
A = Pe^(rt)
A = 11,000 e^(0.0625 × 10)
A = 20,550.71
Compounded semiannually (twice per year):
A = P(1 + r)^t
A = 11,000 (1 + 0.063/2)^(2×10)
A = 11,000 (1 + 0.0315)^20
A = 20,453.96
It’s between B or C
Sorry if I’m wrong
9514 1404 393
Answer:
22.5
Step-by-step explanation:
The average rate of change on the interval [a, b] is the ratio ...
(f(b) -f(x))/(b -a)
For your function and interval, it is ...
(f(0.5) -f(0))/(0.5 -0)
Since f(0) = 0, this reduces to ...
average rate of change = 2·f(0.5) = 2(5(0.5)² +20(0.5)) = 2(5/4 +10)
average rate of change = 22.5
Answer:
16 years
Step-by-step explanation:
Given data
For the first tree
let the expression for the height be
y=4+x--------------1
where y= the total height
4= the initial height
x= the number of years
For the second tree, the expression is
y=12+0.5x-------------2
Equate 1 and 2
4+x=12+0.5x
x-0.5x=12-4
0.5x= 8
x= 8/0.5
x=16
Hence it will take 16 years for both trees to have the same height