Answer:
(I) (-5) is a zero of P(x)
(II) 5 is a zero of P(x)
(III) (-5/2) is a zero of P(x)
Step-by-step explanation:
<h3>
(I) P(x) = x + 5</h3>
Here, P(x) = x + 5
To find the zeroes of P(x)
let P(x) = 0
∴ x + 5 = 0
∴ x = (-5)
Thus, (-5) is a zero of P(x)
<h3>(II) P(x) = x - 5</h3>
Here, P(x) = x - 5
To find the zeroes of P(x)
let P(x) = 0
∴ x - 5 = 0
∴ x = 5
Thus, 5 is a zero of P(x)
<h3>(III) P(x) = 2x + 5</h3>
Here, P(x) = 2x + 5
To find the zeroes of P(x)
let P(x) = 0
∴ 2x + 5 = 0
∴ 2x = -5
∴ x = (-5/2)
Thus, (-5/2) is a zero of P(x)
<u>-</u><u>TheUnknownScientist</u>
Step-by-step explanation:
4x+10
If x=5
4(5)+10
=20+10
=30
x = -2 is the answer because on the graph there is a point where (-2,-2) so yes x = -2.
Answer:
B ±sqrt((y-k)/a ) + h= x
Step-by-step explanation:
y=a(x-h)^2+k
Subtract k from each side
y-k = a(x-h)^2+k-k
y-k = a(x-h)^2
Divide by a
(y-k)/a = a(x-h)^2/a
(y-k)/a = (x-h)^2
Take the square root of each side
±sqrt((y-k)/a )= sqrt((x-h)^2)
±sqrt((y-k)/a )= (x-h)
Add h to each side
±sqrt((y-k)/a ) + h= (x-h+h)
±sqrt((y-k)/a ) + h= x
is the number of terms in the sequence
is the starting term
is the common difference among the terms