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UNO [17]
2 years ago
8

Find the sum of the first 63 terms of –19, -13, -7 …

Mathematics
1 answer:
Degger [83]2 years ago
7 0

You can tell this is an arithmetic sequence because it is a list of terms beginning with -19 that increase by 6 each term. Because of this, we can use the formula for the sum of an arithmetic sequence, which is:

S = \dfrac{n}{2}[2 a_1 + d(n - 1)]

  • n is the number of terms in the sequence
  • a_1 is the starting term
  • d is the common difference among the terms

In this case, we can see that n = 63, a_1 = -19, and d = 6. Thus, we can use the formula:

S = \dfrac{63}{2} [2(-19) + 6(62)] = 10,521


Our answer is 10,521.


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Your schools talent show will feature 12 solo acts and ensemble 2 acts. The show will last 90 min. The 6 solo performers judged
kicyunya [14]
A.  12*x + 2*y = 90
       6*x + 2*y = 60

To write system of equation you just need to sum all solo and ensemble acts and make it equal to how much they will last for.

B.  Here we can multiply second equation with negative 1 and add it to first equation.
6x = 30
x = 5

now we replace x in any of 2 equations to get y.
30+2y = 60
2y = 30
y=15

Solo acts are 5 minutes long and ensemble acts are 15 minutes long
3 0
3 years ago
C(25,10)<br> Find permutation and combination
Verizon [17]

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6 0
2 years ago
What equation is graphed in this figure?
bixtya [17]
The answer is C

Here is the process, hope it helps!
y+2=-3/2(x-2)
y+2=-3/2x+3
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4 0
3 years ago
Which choice is equivalent to the product below when x&gt;0?
V125BC [204]

Answer:

D

Step-by-step explanation:

Using the rule of radicals

\sqrt{\frac{a}{b} } = \frac{\sqrt{a} }{\sqrt{b} }

\sqrt{a\\} × \sqrt{b} ⇔ \sqrt{ab}

Given

\sqrt{\frac{6}{x} } × \sqrt{\frac{x^2}{24} }

= \frac{\sqrt{6} }{\sqrt{x} } × \frac{x^2}{24}

= \frac{\sqrt{6} }{\sqrt{x} } × \frac{x}{2 \sqrt{6\\} }

Cancel \sqrt{6} on numerator/ denominator

= \frac{1}{\sqrt{x} } × \frac{x}{2\\}

= \frac{1}{\sqrt{x} } × \frac{(\sqrt{x})^2 }{2}

Cancel \sqrt{x} on numerator/ denominator, leaving

= \frac{\sqrt{x} }{2} → D

4 0
3 years ago
Hey can you please help me posted picture of question
MAXImum [283]
The correct answer is option B

(5 + 3i)(4+ 2i)

= 5(4+2i) + 3i(4+2i)

= 20 +10i + 12i +6i²

= 20 +22i +6(-1)

= 20 + 22i - 6

= 14 + 22i
5 0
3 years ago
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