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3 years ago

6=g+8. Solving one step Equations

Mathematics

1 answer:

skelet666 [1.2K]3 years ago

7 0

Answer:

g = -2

Step-by-step explanation:

6=g+8

Subtract 8 from each side

6-8=g+8-8

-2 =g

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Help me this is due tommorow

Ann [662]

Answer:

Step-by-step explanation:

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3 years ago

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A woman bought some large frames for $10 each and some small frames for $5 each add a closeout sale if she bought 20 frames for

vampirchik [111]

Answer:

The quantity of large frames is 7

The quantity of small frames is 13

Step-by-step explanation:

Given as :

The price of each large frames = $ 10

The price of each small frames = $ 5

The total number of both frames bought = 20

The price for both the frames = $ 135

Now,

Let the quantity of large frames = L

And The quantity of small frames = S

So , According to question

The total number of both frames bought = 20

Or, The quantity of large frames + the quantity of small frame = 135

Or, L + S = 20 ......A

And $ 10 L + $ 5 S = $ 135 ................B

Or, $ 10× ( L + S ) = $ 10× 20

Or, $ 10 L + $ 10 S = $ 200

( $ 10 L + $ 10 S ) - ( $ 10 L + $ 5 S ) = $ 200 - $ 135

Or , ( $ 10 L - $ 10 L ) + ( $ 10 S - $ 5 S ) = $ 65

Or, 0 + 5 S = 65

∴ S = $\frac{65}{5}$

I.e S = 13

So, The quantity of small frames = S = 13

Put the Value of S in eq A

So , L + S = 20

Or, L = 20 - S

Or, L = 20 - 13

∴ L = 7

So, The quantity of large frames = L = 7

Hence The quantity of large frames is 7

And The quantity of small frames is 13 Answer

7 0

3 years ago

Write the equation of the line y=(5)/(6)x+(7)/(6) perpendicular to

Travka [436]

Answer:

6x + 5y + 13 = 0.

Step-by-step explanation:

y = 5/6x + 7/6

Gradient = 5/6

Since the line is perpendicular to y = 5/6x + 7/6

then its gradient is -6/5.

Hence its equation is: point (-8,7).

y - 7 = -6/5(x -(-8))

multiplying through by 5 we get;

5y - 35 = -6(x + 8)

5y - 35 = -6x - 48

6x + 5y + 13 = 0

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2 years ago

What is the equation of the line that passes through the points (15, 9) and (Negative 2, 9)? y =

Bad White [126]

$\bf (\stackrel{x_1}{15}~,~\stackrel{y_1}{9})\qquad (\stackrel{x_2}{-2}~,~\stackrel{y_2}{9}) ~\hfill \stackrel{slope}{m}\implies \cfrac{\stackrel{rise} {\stackrel{y_2}{9}-\stackrel{y1}{9}}}{\underset{run} {\underset{x_2}{-2}-\underset{x_1}{15}}}\implies \cfrac{0}{-17}\implies 0 \\\\\\ \begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-\stackrel{y_1}{9}=\stackrel{m}{0}(x-\stackrel{x_1}{15})\implies y-9=0\implies y=9$

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the half-life of strontium-90 is approximately 29 years. how much of a 500 g sample of strontium-90 will remain after 58 years

Yuliya22 [10]

Answer: 125 g

<u>Step-by-step explanation:</u>

$A = P_o\cdot e^{kt}\\\\\text{First, use the given information to find k:}\\\\\bullet A=\dfrac{1}{2}P_o\\\\\bullet k = unknown\\\\\bullet t=29\text{ years}\\\\\dfrac{1}{2}P_o=P_o\cdot e^{k(29)}\\\\\\\dfrac{1}{2}=e^{k(29)}\qquad divided\ both\ sides\ by\ P_o\\\\\\ln\bigg(\dfrac{1}{2}\bigg)=ln\bigg(e^{k(29)}\bigg)\qquad applied\ ln\ to\ both\ sides\\\\\\ln\bigg(\dfrac{1}{2}\bigg)=29k\qquad simplified-ln\ and\ e\ cancel\ out\\\\\\\dfrac{ln\bigg(\dfrac{1}{2}\bigg)}{29}=k\qquad divided\ 29\ from\ both\ sides\\\\\\-0.0239=k$

$\text{Now, use the following in the equation to solve for A:}\\\\\bullet A=unknown\\\bullet P_o=500\\\bullet k=-0.0239\\\bullet t=58\text{ years}\\\\A=500\cdot e^{(-0.0239)(58)}\\\\.\quad=500\cdot e^{-1.386}\\\\.\quad=125$

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3 years ago