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Zielflug [23.3K]

3 years ago

9

1. Imagine a 10 by 10 square with the outside edge colored red. Without using paper or counting them individually how many red s

quares will there be. 2. Explain why you think your answer is correct. How did you "see" it? 3. What if it was a 100 by 100 square? How many red squares would there be? 4. What mathematical expression could you use to represent the number of red squares for any size rectangle?

1 answer:

Allushta [10]3 years ago

8 0

Answer:

36, 396, thats all i gots

Step-by-step explanation:

You might be interested in

There were 42 students who took a test in mathematics.there were 36 students who passed test 1, and there were 38 who passed tes

Keith_Richards [23]

We are giiven with two realms: 36 students who passed test 1 and <span>38 who passed test 2 in which 42 students overall took the test. to determine U' or those who didn't pass either of the tests, then we use the formula:
A or B = (A+B)-AandB
A/B = (36+38)-AandB= 74-AandB
42 = A+ B - AandB + U'; 42 = 74- AandB+ U'

where U' is the number who did not pass

U'= -32 + AandB
U' cannot be negative but can be zero,
AandB = 32 @ minimum number of those who fail.
AandB cannot be greater than 38 but can be greater than 36, hence
U' = -32 + 38 @ maximum number of those who fail.

Answer then is 6.

</span>

7 0

2 years ago

Anne, Barry, and Cathy enter a coffee shop. Anne orders two coffees, one juice, and two doughnuts and pays $7.50. Barry orders o

Evgesh-ka [11]

Answer:

Coffee = $2.00

Juice = $1.50

Doughnut = $1.00

Step-by-step explanation:

Given

Let:

$c = coffee\\ j= juice\\ d = doughnut$

So, we have:

Anna

$2c + j + 2d = 7.50$

Barry

$c + 3d = 5.00$

Cathy

$3c + j + 4d = 11.50$

Required

The price of each

We have:

$2c + j + 2d = 7.50$

$c + 3d = 5.00$

$3c + j + 4d = 11.50$

Make c the subject in: $c + 3d = 5.00$

$c = 5.00 - 3d$

Substitute $c = 5.00 - 3d$ in $2c + j + 2d = 7.50$ and $3c + j + 4d = 11.50$

$2c + j + 2d = 7.50$

$2[5.00 - 3d] + j + 2d = 7.50$

$10.00 - 6d+ j + 2d = 7.50$

Make j the subject

$j = 7.50 - 10.0 +6d - 2d$

$j = -2.50 +4d$

$3c + j + 4d = 11.50$

$3[5.00 - 3d] + j + 4d = 11.50$

$15.00 - 9d + j + 4d = 11.50$

Make j the subject

$j = 11.50 - 15.00 + 9d -4d$

$j = -3.50 + 5d$

So, we have:

$j = -3.50 + 5d$ and $j = -2.50 +4d$

Equate both values of j

$-3.50 + 5d = -2.50 + 4d$

Collect like terms

$5d - 4d = 3.50 -2.50$

$d = 1.00$

Substitute $d = 1.00$ in $j = -3.50 + 5d$

$j = -3.50 + 5d$

$j = -3.50 + 5 * 1.00$

$j = -3.50 + 5.00$

$j = 1.50$

To solve for c, we substitute $d = 1.00$ in $c + 3d = 5.00$

$c + 3 * 1.00 =5.00$

$c + 3.00 =5.00$

Solve for c

$c =- 3.00 +5.00$

$c =2.00$

7 0

2 years ago

Write a fraction less than 1 with a denominator of 6 that is greater than 3/4

serg [7]

The answer you are looking for is 5/6

7 0

3 years ago

Read 2 more answers

What is the decimal representation of seven hundredths

irakobra [83]

0.07 or .07 is the same

6 0

3 years ago

A mining company estimates that the marginal cost of extracting x tons of copper ore from a mine is 0.6 + 0.008x, measured in th

Serhud [2]

Answer:

The cost of extracting the first 50 tons of copper is $151,000.

Step-by-step explanation:

Start-up costs of $150,000.

For the 50 tons of cooper.

$C(x) = 0.6 + 0.008x$

So

$C(50) = 0.6 + 0.008*50 = 1$

1 thousand dollars.

So

$150,000 + $1,000 = $151,000

The cost of extracting the first 50 tons of copper is $151,000.

8 0

2 years ago