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3 years ago

Help plz 20 points.. tysm

Mathematics

2 answers:

emmainna [20.7K]3 years ago

7 0

B in parlimentary only chosen members get to vote but in a presidential everyone gets to vote

Natali5045456 [20]3 years ago

3 0

Answer:

<em>The citizens have the right to vote.</em>

Step-by-step explanation:

In a parliament, only select members of the legislature are allowed to vote, while in a presidential democracy all the votes belong to the citizens.

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Quick! Need the answer

zvonat [6]

Replace the x in the equation with the given value of x and you will find that the 3rd equation is corret.

F(X) = 4(1/2)^X

4(1/2)^-2 = 4 * 4 = 16

6 0

2 years ago

10•f(7)+9•g(-1)? What’s the answerrr

Inessa [10]

Answer:

= 70f - 9g

Step-by-step explanation:

1. Remove parentheses

2. Multiply the numbers

3. Multiply the numbers

5 0

3 years ago

State the reason why MN = LK.

Fudgin [204]

I hope this helps you

5 0

3 years ago

Find the radius of convergence, then determine the interval of convergence

galben [10]

The radius of convergence R is 1 and the interval of convergence is (-3, -1) for the given power series. This can be obtained by using ratio test.

<h3>Find the radius of convergence R and the interval of convergence:</h3>

Ratio test is the test that is used to find the convergence of the given power series.

First aₙ is noted and then aₙ₊₁ is noted.

For ∑ aₙ, aₙ and aₙ₊₁ is noted.

$\lim_{n \to \infty} |\frac{a_{n+1}}{a_{n} }|$ = β

If β < 1, then the series converges

If β > 1, then the series diverges

If β = 1, then the series inconclusive

Here $a_{k}$ = $\frac{(x+2)^{k}}{\sqrt{k} }$ and $a_{k+1}$ = $\frac{(x+2)^{k+1}}{\sqrt{k+1} }$

Now limit is taken,

$\lim_{n \to \infty} |\frac{a_{n+1}}{a_{n} }|$ = $\lim_{n \to \infty} |\frac{(x+2)^{k+1} }{\sqrt{k+1} }/\frac{(x+2)^{k} }{\sqrt{k} }|$

= $\lim_{n \to \infty} |\frac{(x+2)^{k+1} }{\sqrt{k+1} }\frac{\sqrt{k} }{(x+2)^{k}}|$

= $\lim_{n \to \infty} |{(x+2) } }{\sqrt{\frac{k}{k+1} } }}|$

= $|{x+2 }|\lim_{n \to \infty}}{\sqrt{\frac{k}{k+1} } }}$

= $|{x+2 }|$ < 1

- 1 < ${x+2 }$ < 1

- 1 - 2 < x < 1 - 2

- 3 < x < - 1

We get that,

interval of convergence = (-3, -1)

radius of convergence R = 1

Hence the radius of convergence R is 1 and the interval of convergence is (-3, -1) for the given power series.

Learn more about radius of convergence here:

brainly.com/question/14394994

#SPJ1

5 0

1 year ago

Read 2 more answers

Simplify 9(x+7)^2/3(x-1)(x+7)

sladkih [1.3K]

9/3 =3
(X+7)^2/ (x+7) = x+7
1/x-1

3(x+7)/x-1

3x+21/x-1

5 0

3 years ago