All categories

3 years ago

Pleaseeee heeellllppppp

Mathematics

1 answer:

yan [13]3 years ago

4 0

Answer:

i believe it's 1/3

Step-by-step explanation:

You might be interested in

Find the missing coefficients <br><br><br>y=ax^2-10x+c <br>vertex :(-5,20)

Citrus2011 [14]

Remember, for $y=ax^2+bx+c$ the x value of the vertex is $\frac{-b}{2a}$

so
given
x value of vertex is -5
and
$y=ax^2-10x+c$
$\frac{-b}{2a}=\frac{-(-10)}{2a}=\frac{10}{2a}=$
$\frac{5}{a}=-5$
multiply both sides by a
5=-5a
divvide both sides by -5
-1=a
a=-1

$y=-1x^2-10x+c$
comlete the square
remember if we do
$y=a(x-h)^2+k$ (h,k) is the vertex
I know, we can subsitute the known values of te vertex
-5 for h and 20 for k then expand

$y=-1(x-(-5))^2+20$
$y=-1(x+5)^2+20$
$y=-1(x^2+10x+25)+20$
$y=-1x^2-10x-25+20$
$y=-1x^2-10x-5$

a=-1
c=-5

5 0

3 years ago

Find the area of a circle shaped swimming pool with a diameter of 22 meters. Use 3.14 the area of the circle is approximately ho

Kay [80]

Answer: 379.94

Step-by-step explanation: To find the area of a circle, you do radius squared times pi. To find the radius, divide the diameter in half. So 22 divided by 2 is 11. 11 squared is 121. Then multiply 121 by 3.14. That equals to 379.94

4 0

3 years ago

Read 2 more answers

In terms of x, find an expression that represents the area of the shaded region. The outer square has side lengths of (x+5) and

VLD [36.1K]

The area of the outer square = (x+5)² = x² + 10x + 25

The area of the inner square = (x-2)² = x² - 4x + 4

The area of the shaded region = (x² + 10x + 25) - (x² - 4x + 4)
= x² + 10x + 25 - x² + 4x - 4
= 14x + 21 square units

6 0

3 years ago

How do we post a picture?

svet-max [94.6K]

Answer:

click on the thing that looks like a paper clip and pick the pic u wanna post

Step-by-step explanation:

3 0

3 years ago

What is the justification for each step in the solution of the equation?

ollegr [7]

54+2x=5x−6−18x54+2x=5x−6−18x addition , division, multiplucation
this step is wrong

5 0

3 years ago