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BabaBlast [244]
3 years ago
8

What is the sum of the two vectors (-1,-4) and (3,5)

Mathematics
2 answers:
o-na [289]3 years ago
5 0

Answer:

Step-by-step explanation:

a(-1, -4)\\b(3, 5)\\a + b(2, 1)

harina [27]3 years ago
4 0

Answer:

(2,1)

Step-by-step explanation:

Just took the quiz

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HELP geometry pls angle measurements
olya-2409 [2.1K]
Angle 2 is vertical to angle 1 which would make it EQUAL to angle 1 (angle 2 is 133 degrees) then you subtract 133 from 180 which will leave you with 47.

Answer: angle 2 is 133 and angle 3 is 47.
3 0
3 years ago
Solve the following equation <br><br>6x-1=3 (2x+4)-1
DIA [1.3K]
6x - 1 = 3(2x + 4) - 1
Distribute
6x - 1 = 6x + 12 - 1
Combine like terms
6x - 1 = 6x + 11
Add 1 and subtract 6x from each side
0 = 12
The equation has no real solution
4 0
3 years ago
Read 2 more answers
A small class has 10 students, 4 of whom are girls and 6 of whom are boys. The teacher is going to choose two of the students at
Vinil7 [7]

Answer:

1/3

Step-by-step explanation:

Dividing the amount of boys (6) by the amount of students (10), and then reiterating that, subtracting 1 from both, you get:
(6/10) x (5/9) which equals a third.

7 0
2 years ago
Estimate. then find the sum. 1.20 plus 0.34
Trava [24]
1.20 + 0.34 = 1.54
That is the answer.
5 0
3 years ago
Read 2 more answers
11/ 42 Marks
amm1812

Answer:

(a)x=128 degrees

(b)\angle APD\neq 116^\circ

Step-by-step explanation:

\angle ABD+\angle CBD =180^\circ$ (Linear Postulate)\\\angle ABD+116^\circ =180^\circ\\\angle ABD=180^\circ-116^\circ\\\angle ABD=64^\circ

(a) Now:

\angle AOD=2 \times \angle ABD$ (Angle at the centre is twice the  angle at the circumference)\\x=2 \times 64^\circ\\x=128^\circ

(b)

\angle APD=2 \times \angle ABD$ (Inscribed Angle Theorem)\\\angle APD=2 \times 64^\circ\\ \angle APD=128^\circ

\angle APD\neq 116^\circ

7 0
3 years ago
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