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Serga [27]
1 year ago
6

What is the equation of the line that passes through the point (4. -2) and has a slope of 5/4?

Mathematics
1 answer:
KIM [24]1 year ago
7 0

Answer:

y = 5/4 x - 7

Step-by-step explanation:

y - y1 = m(x - x1)

y + 2 = 5/4 (x - 4)

y + 2 = 5/4 x - 5

y = 5/4 x - 7

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For what value of x is the equation 8x-2(x-7)=20 true?
sukhopar [10]

Answer:

x = 1

Step-by-step explanation:

Given

8x - 2(x - 7) = 20 ← distribute parenthesis on left side

8x - 2x + 14 = 20, that is

6x + 14 = 20 ( subtract 14 from both sides )

6x = 6 ( divide both sides by 6 )

x = 1

6 0
3 years ago
Find the product.<br> 0.00461 x<br> 105
Elena L [17]
The correct answer is 0.48405
3 0
3 years ago
Read 2 more answers
steven can type 160 words in 2 minutes and 30 seconds at this rate, how many words can he type in 4 minutes?
Gnom [1K]

Answer:

hello : 256 words

Step-by-step explanation:

2 minutes and 30 = (2×60)+30=150seconds

4 minutes = 4 ×60 = 240 seconds

 150seconds  →160 words

240 seconds → x ?

x = (160×240) / 150 = 38400/150= 256 words

6 0
3 years ago
please i have been stuck on thos math problem for 123 minutes ago please help please I'm stressing out please I urgently need he
alisha [4.7K]

Answer:

it could be    1. c      2. a      3. d      4. b

or it could be the answers i did for last time in the pic: (that is my old account that got banned)

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8 0
3 years ago
A physics exam consists of 9 multiple-choice questions and 6 open-ended problems in which all work must be shown. If an examinee
katrin [286]

Answer: A) 1260

Step-by-step explanation:

We know that the number of combinations of n things taking r at a time is given by :-

^nC_r=\dfrac{n!}{(n-r)!r!}

Given : Total multiple-choice questions  = 9

Total open-ended problems=6

If an examine must answer 6 of the multiple-choice questions and 4 of the open-ended problems ,

No. of ways to answer 6 multiple-choice questions

= ^9C_6=\dfrac{9!}{6!(9-6)!}=\dfrac{9\times8\times7\times6!}{6!3!}=84

No. of ways to answer 4 open-ended problems

= ^6C_4=\dfrac{6!}{4!(6-4)!}=\dfrac{6\times5\times4!}{4!2!}=15

Then by using the Fundamental principal of counting the number of ways can the questions and problems be chosen = No. of ways to answer 6 multiple-choice questions x No. of ways to answer 4 open-ended problems

= 84\times15=1260

Hence, the correct answer is option A) 1260

5 0
3 years ago
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