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3 years ago

If the 1st and 10th terms of geometric sequence are 4 and 100. Fine the nth term of the sequence

1 answer:

3 0

A(n)=ar^(n-1) so

100=4r^9

25=r^9

ln25=9lnr

ln25/9=lnr

r=e^(ln25/9)

a(n)=4e^((n-1)(ln25/9) if you wanted an approximation...

a(n)=4(1.43^(n-1))

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jek_recluse [69]

Answer:

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Step-by-step explanation:

7 0

3 years ago

Read 2 more answers

A cold tablet contains the following amounts of active ingredients: acetaminophen 325 mg, chlorpheniramine maleate 2 mg, and dex

kakasveta [241]

Answer:

The number of tablets that can be prepared is 3076.

Step-by-step explanation:

The total amount of active ingredients in the tablet is the sum of the amounts provided in the formula:

$325 mg + 2mg+15 mg=342 mg$

The percentages of each component in the formula are:

Acetaminophen: $\frac{325mg*100}{342mg}=95.03$ %

Chlorpheniramine maleate: $\frac{2mg*100}{342mg} =0.58$ %

Dextromethorphan hydrobromide: $\frac{15mg*100}{342mg}=4.39$ %

If 1 Kg= $10^{6}$ mg of acetaminophen is used, the needed amount of chlorpheniramine maleate would be:

$\frac{10^{6} mg *0.58}{95.03}=6153.85 mg$

Since there are 125 g = 125000 mg of chlorpheniramine maleate, there is enough of these ingredient to run the available acetaminophen out. Thus, the total amount of active ingredients that can be prepared with 1 kg of acetaminophen is:

$\frac{10^{6}mg*100}{95.03}=1052307.7mg$

Since each tablet weighs 342 mg, the number of tablets that can be prepared is:

$\frac{1052307.7mg}{342mg}=3076.923$

Which means that 3076 tablets can be prepared and a there will be a remanent of 0.923*342 mg = 315.69 mg of active ingredients.

7 0

3 years ago

Solve the proportion. 47/39 = b/2 A: 94/39 B: 78/47 C: 47/78 D: 39/94

pshichka [43]

Answer:

b = 94/79

Step-by-step explanation:

47/79 = x/2

79x = 94

x = 94/79

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2 years ago

Do you expect 1/n to be larger or smaller than 1/n+1?Do you expect 1/n to be larger or smaller than 1/n+2? Explain why.

Fudgin [204]

Answer:

Step-by-step explanation:

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5 0

3 years ago

A piggy bank contains pennies, nickels, and dimes. The number of dimes is 15 more than the number of nickels, and there are 140

amm1812

Answer:

Option D is correct.

There are 34 nickels in the piggy bank.

Step-by-step explanation:

A piggy bank contains pennies, nickels and dimes.

Let the number of pennies be p

Let the number of nickels be n

Let the number of dimes be d

Also, note that 1 penny = $0.01

1 nickel = $0.05

1 dime = $0.10

- The number of dimes is 15 more than the number of nickels.

d = 15 + n

- There are 140 coins altogether totaling $7.17.

p + n + d = 140

0.01p + 0.05n + 0.1d = 7.17

Bringing the 3 equations together

d = 15 + n (eqn 1)

p + n + d = 140 (eqn 2)

0.01p + 0.05n + 0.1d = 7.17 (eqn 3)

Substitute (eqn 1) into (eqn 2)

p + n + d = 140

p + n + (15 + n) = 140

p + 2n + 15 = 140

p = 140 - 15 - 2n = 125 - 2n

p = 125 - 2n (eqn 4)

Substitute (eqn 1) and (eqn 4) into (eqn 3)

0.01p + 0.05n + 0.1d = 7.17

0.01(125 - 2n) + 0.05n + 0.1(15 + n) = 71.7

1.25 - 0.02n + 0.05n + 1.5 + 0.1n = 7.17

0.1n + 0.05n - 0.02n + 1.5 + 1.25 = 7.17

0.13n + 2.75 = 7.17

0.13n = 7.17 - 2.75 = 4.42

0.13n = 4.42

n = (4.42/0.13) = 34

d = 15 + n = 15 + 34 = 49

p = 125 -2n = 125 - (2×34) = 125 - 68 = 57

Hence, there are 57 pennies, 34 nickels and 49 dimes in the piggy bank.

Hope this Helps!!!

7 0

3 years ago