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3 years ago

(y 3 - 4y 2 + 7y - 6) (y - 2)

1 answer:

8 0

Y^4-4y^3+7y^2-6y-2y^3+8y^2-14y+12=
y^4-6y^3+15y^2-20y+12

or

y^3-4y^2+7y-6=y^3-4y^2+4y+3y-6=
y(y^2-4y+4)+3(y-2)=
y(y-2)^2+3(y-2)=(y-2)[y(y-2)+3]=(y-2)(y^2-2y+3)

(y^3-4y^2+7y-6)(y-2)=(y-2)^2(y^2-2y+3)

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What are the unit rates? FOR ALL OF THEM.

kykrilka [37]

Francios $19.48 per hour Carissa $14 per hour Garrick $19.04 per hour Arianne $25.71 per hour

7 0

2 years ago

In ΔWXY, the measure of ∠Y=90°, XW = 53, YX = 28, and WY = 45. What is the value of the cosine of ∠X to the nearest hundredth?

kotegsom [21]

The value of ∠X = 58.11°, If ΔWXY, the measure of ∠Y=90°, XW = 53, YX = 28, and WY = 45.

Step-by-step explanation:

The given is,

In ΔWXY, ∠Y=90°

XW = 53

YX = 28

WY = 45

Step:1

Ref the attachment,

Given triangle XWY is right angled triangle.

Trigonometric ratio's,

$Cos$ ∅ $= \frac{Adj}{Hyp}$

For the given attachment, the trigonometric ratio becomes,

$Cos$ ∅ $= \frac{XY}{XW}$ .....................................(1)

Let, ∠X = ∅

Where, XY = 28

XW = 53

Equation (1) becomes,

$Cos$ ∅ $= \frac{28}{53}$

$Cos$ ∅ = 0.5283

∅ = $cos^{-1}$ (0.5283)

∅ = 58.109°

Result:

The value of ∠X = 58.11°, If ΔWXY, the measure of ∠Y=90°, XW = 53, YX = 28, and WY = 45.

4 0

2 years ago

A:1/360 B:1/90 C:1/180 D:1/100

valkas [14]

the answer is 1/360.

$\frac{1}{1} = 360degrees \\ x= 1degree$

cross multiplication and u get the answer

5 0

3 years ago

Find the arc length of the partial circle.

Kay [80]

Answer:

12.42 units

Step by step explanation:

Given,

length of the radius = 2 units

Therefore, arc length of the complete circle = 2 × 3.14 × 2 units = 12.56 units

Therefore, arc length of the partial circle = 3/4 × 12.56 units

= 12.42 units

3 0

2 years ago

72 + 8x + 18x = 36x

ArbitrLikvidat [17]

$72 + 8x + 18x = 36x
$

$72+26x=36x
$

$72=36x-26x
$ $\text{Subtract 26x from both sides}$

$72=10x
$

$\text{Divide both sides by 10}$

$x=36/5$

4 0

2 years ago