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3 years ago

(y 3 - 4y 2 + 7y - 6) (y - 2)

1 answer:

8 0

Y^4-4y^3+7y^2-6y-2y^3+8y^2-14y+12=
y^4-6y^3+15y^2-20y+12

or

y^3-4y^2+7y-6=y^3-4y^2+4y+3y-6=
y(y^2-4y+4)+3(y-2)=
y(y-2)^2+3(y-2)=(y-2)[y(y-2)+3]=(y-2)(y^2-2y+3)

(y^3-4y^2+7y-6)(y-2)=(y-2)^2(y^2-2y+3)

You might be interested in

Factor 5x4 - 30x2 - 135.

lakkis [162]

Answer:

-175

Step-by-step explanation:

5x4=20

30x2=60

20-60=-40

-40-135=175

I hope this helps!

7 0

3 years ago

How do you get the average of something

kogti [31]

The mean is the average of the numbers. It is easy to calculate: add up all the numbers, then divide by how many numbers there are. In other words it is the sum divided by the count.

6 0

3 years ago

Read 2 more answers

The width of a rectangular room is 80% of its length. If the length of the room is 20 meters, what is the area of the room? A= l

KIM [24]

Answer:320ft^2

Step-by-step explanation:

80% of 20 is 16, because 80% is 4/5 and 20 divided by 5 is 4, multiplied by 4 is 16. Area is L x W, so 16 times 20 is 320, and don't forget unit of measurement, ft^2 for area

7 0

3 years ago

Read 2 more answers

Shu Yi can't resist a sale. She recently bought a dress for $93 after it had been discounted 25%. She also purchased shoes that

klemol [59]

Dress: 93$ at 100-25%=75%
-> divide the marked down cost by the percentage to get the cost of a single percent and then multiply it with the markdown again to get the saved cost
93/75*25=93/3*1=31*1=31$
shoes 119$ at 100-15%=85%
119/85*15=119/17*3=7*3=21

add both savings together for the full sum: 31+21=52$

8 0

3 years ago

A circular pool measures 10 feet across. one cubic yard of concrete is to be used to create a circular border of uniform width a

mina [271]

we know that

1 ft is equal to 12 in

1 cubic yard is equal to 27 cubic feet

Step 1

<u>Find the area of the circular border of uniform width around the pool</u>

Let

x---------> the uniform width around the pool

we know that

The diameter of the circular pool measures 10 feet

the radius r=5 ft

the area of the circular border is equal to

$A=\pi *(5+x)^{2}- \pi *5^{2} \\A= \pi *[(x+5) ^{2}-5^{2} ] \\ A= \pi * [x^{2} +10x]$

step 2

volume of the concrete to be used to create a circular border is equal to

V=1 yd^{3}-------> convert to ft^{3}

V=27 ft^{3} -------> equation 1

the depth is equal to 4 in-------> convert to ft

depth=4/12=(1/3) ft

volume of the concrete to be used to create a circular border is also equal to

V=Area of the circular border*Depth

$V= \pi * [x^{2} +10x]*(1/3)$ -------> equation 2

equate equation 1 and equation 2

$27=\pi * [x^{2} +10x]*(1/3) \\ x^{2} +10x- \frac{81}{\pi }=0$

using a graph tool------> to resolve the second order equation

see the attached figure

the solution is the point

x=2.126 ft

therefore

<u>the answer is</u>

The uniform width around the circular pool border is 2.126 ft

7 0

3 years ago