All categories

2 years ago

(y 3 - 4y 2 + 7y - 6) (y - 2)

1 answer:

8 0

Y^4-4y^3+7y^2-6y-2y^3+8y^2-14y+12=
y^4-6y^3+15y^2-20y+12

or

y^3-4y^2+7y-6=y^3-4y^2+4y+3y-6=
y(y^2-4y+4)+3(y-2)=
y(y-2)^2+3(y-2)=(y-2)[y(y-2)+3]=(y-2)(y^2-2y+3)

(y^3-4y^2+7y-6)(y-2)=(y-2)^2(y^2-2y+3)

You might be interested in

Does anyone know the answer!!!!

egoroff_w [7]

Answer:

Step-by-step explanation:

3 0

2 years ago

Read 2 more answers

What is 10 to the power of 6

Yakvenalex [24]

10^6 can also be written as 10*10*10*10*10*10 which is equal to 1000000 (1 million)

Hope it helps :)

8 0

2 years ago

Read 2 more answers

A roped-off area of width x is created around a 30- by 10-foot rectangular museum display of Native American artifacts. The comb

Monica [59]

Answer: $4x^{2}+80x-500=0$

Step-by-step explanation:

1. You know that:

- The roped-off area whose width is represented with x, it is created around a rectangular museum.

- The dimensions of the rectangular museum are: 30 ft by 10 ft.

- The combined area of the display and the roped-off area is 800 ft².

2. The area of the rectangular museum can be calculated with:

$A=l*w$

Where $l$ is the lenght and $w$ is the width.

You have that the lenght and the width in feet are:

$l=30\\w=10$

3. Let's call $x$ the width of the roped-off area. Then, the combined area is:

$A_c=l_c*w_c$

Where

$A_c=800$

$l_c=l+x+x=30+2x$

$w_c=w+x+x=10+2x$

4. Substitute values and simplify. Then:

$800=(30+2x)(10+2x)$

$800=300+60x+20x+4x^{2}\\4x^{2}+80x-500=0$

5 0

3 years ago

Solve by the elimination method. Show your work 2x – 5y = 1 3x – 4y = -2

svlad2 [7]

Hello,

2x-5y=1 |3|4
3x-4y=-2|-2|-5
------------------------

-7y=7 ==>y=-1
-7x=14==>x=-2

sol={(-2,-1)}

3 0

2 years ago

+) Evaluate the expression 81 – 82. 81 – 82 =

Temka [501]

81 - 8^2 is 17 ..............

7 0

2 years ago

Read 2 more answers