13/25 because I got the answer right
Answer:
y = 2x
the rise is the 2, and the the run is positive 1, because with graphing its always rise/run, and if there isn't anything below it, it is 2x/1
Answer:
The maximum height of the projectile is 90 ft
Step-by-step explanation:
Here, we want to get the maximum height reached by the projectile
The answer here will be the y-coordinate value of the vertex form of the given equation
so firstly, we have to write the equation in the vertex form
We have this as;
y = -16t^2 + 64t + 26
That will be;
y = a(x-h)^2 + k
y = -16(x-2)^2 + 90
where the vertex of the equation is;
(-h,k)
K
in this case is 90 and thus, that is the maximum height of the projectile
In intercept form, the plane that has these intercepts is ...
... x/(x-intercept) + y/(y-intercept) + z/(z-intercept) = 1
... x/1 + y/(-1) + z/2 = 1
... 2x -2y +z = 2 . . . . . in standard form
