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TiliK225 [7]
3 years ago
10

Please give me the correct answers.Only answer if you're very good at math.Please don't put a link to a website.

Mathematics
1 answer:
SVETLANKA909090 [29]3 years ago
3 0

Answer:

In the left box, type: 2 In the right box, type: 3

Step-by-step explanation:

1/3(4a + 1) = 1/2a

6{1/3(4a + 1)] = 6(1/2a)

because 6 x 1/3 = 2 and 6 x 1/2 = 3

2(4a + 1) = 3a

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Write a linear equation from the ordered pair (-2,8)
OlgaM077 [116]
The equation of a line that goes through the point (x1,y1) and has a slope of m is
y-y1=m(x-x1)

so, given the point (-2,8)
x1=-2
y1=8

y-8=m(x-(-2))
y-8=m(x+2)
the equation is y-8=m(x+2) where m is the slope
or you could rewrite it to get y=mx+2m+8

4 0
3 years ago
What are the coordinates of the vertex for f(x) = 2x2 + 4x + 9?
Vlada [557]
Your equation f(x)=2x^2+4x+9 is in the form y=ax^2+bx+c
The vertex only relies on "a" and "b" though, so that +9 doesn't really matter in this case.  The vertex of a parabola is located where 
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5 0
3 years ago
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What is greater, 85/100 or 21/25?
Elodia [21]


85/100 is greater

85/100=.85 or 85%

21/25=.84 or 84%

.85 is greater than .84 so 85/100 > 21/25

8 0
3 years ago
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What is the equation 2y=x-8 In y intercept form?
Artyom0805 [142]
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5 0
3 years ago
The roosevelt middle school band is having a fundraiser. They sold a total of 300 hotdogs and hamburgers. Hot dogs were sold for
STALIN [3.7K]

Answer:

180 hamburgers

120 hotdogs

Step-by-step explanation:

In this question, we are asked to calculate the number of hamburgers and hotdogs sold by a company given the amount made by them and the total number of these snacks sold

We proceed as follows;

Let the amount of hotdogs sold be x and the amount of hamburgers sold be y.

We have a total of 300 snacks sold, mathematically;

x + y = 300 ..........(I)

Now let’s look at the prices.

x number of hotdogs sold at $2, this give a total of $2x hotdogs

y number of hamburgers sold at $3, this give a total of $3y.

Adding both to give total, we have ;

2x + 3y = 780.......(ii)

This means we have two equations to solve simultaneously. From equation 1, we can say x = 300 -y

Now let’s insert this in the second equation;

2(300-y) + 3y = 780

600-2y + 3y = 780

y = 780-600 = 180

Recall; x + y = 300

x = 300 -y

x = 300-180 = 120

5 0
3 years ago
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