1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
alina1380 [7]
3 years ago
12

.Let F(x,y)= (y^2+1i + (2xy-2)j. Compute single integral with subscript of C F * dr where

Mathematics
1 answer:
Bess [88]3 years ago
4 0

I do not know if this is exactly what you are looking for

You might be interested in
Can someone solve this?
RoseWind [281]
I can the company sold 3,00 units in 2008, and 5,00 in 2012
3 0
3 years ago
2. Which of the following is a quadratic equation?
Liula [17]

Answer:

1 111111111818182818282

6 0
3 years ago
18 points for 2 questions. I really appreciate your help! :)
nikitadnepr [17]
10. (1,-1)
19. clockwise 90 degrees; enlargement
8 0
3 years ago
Read 2 more answers
An equilateral triangle is inscribed in a circle of radius 6r. Express the area A within the circle but outside the triangle as
Paul [167]

Answer:

A(x)=\frac{100\pi x^2-75\sqrt{3}x^2}{12}

Step-by-step explanation:

We have been given that an equilateral triangle is inscribed in a circle of radius 6r. We are asked to express the area A within the circle but outside the triangle as a function of the length 5x of the side of the triangle.

We know that the relation between radius (R) of circumscribing circle to the side (a) of inscribed equilateral triangle is \frac{a}{\sqrt{3}}=R.

Upon substituting our given values, we will get:

\frac{5x}{\sqrt{3}}=6r

Let us solve for r.

r=\frac{5x}{6\sqrt{3}}

\text{Area of circle}=\pi(6r)^2=\pi(6\cdot \frac{5x}{6\sqrt{3}})^2=\pi(\frac{5x}{\sqrt{3}})^2=\frac{25\pi x^2}{3}

We know that area of an equilateral triangle is equal to \frac{\sqrt{3}}{4}s^2, where s represents side length of triangle.

\text{Area of equilateral triangle}=\frac{\sqrt{3}}{4}s^2=\frac{\sqrt{3}}{4}(5x)^2=\frac{25\sqrt{3}}{4}x^2

The area within circle and outside the triangle would be difference of area of circle and triangle as:

A(x)=\frac{25\pi x^2}{3}-\frac{25\sqrt{3}x^2}{4}

We can make a common denominator as:

A(x)=\frac{4\cdot 25\pi x^2}{12}-\frac{3\cdot 25\sqrt{3}x^2}{12}

A(x)=\frac{100\pi x^2-75\sqrt{3}x^2}{12}

Therefore, our required expression would be A(x)=\frac{100\pi x^2-75\sqrt{3}x^2}{12}.

7 0
3 years ago
Stacy decided that she would start doing sit ups every day. Her plan each day was to do twice as many sit ups as she had done th
Whitepunk [10]

Answer:

Day five= 32 sit ups

Step-by-step explanation:

Day 1= 2 sit ups

Day 2= 4 sit ups

Day 3= 8 sit ups

Day 4= 16 sit ups

Day 5= 32 sit ups

8 0
3 years ago
Other questions:
  • How do I find the width in a frequency distribution?
    11·1 answer
  • 2. Find the distance between M(1,-2) and N (9, 13).
    5·1 answer
  • Divide 169 mi in the ratio 5 : 8.
    8·1 answer
  • HELP I HAVE ONLINE CLASS QUESTIONS DUE TODAY
    6·1 answer
  • Find the value of x, rounded to the nearest tenth
    9·1 answer
  • What is 6x+5y= -15 converted to slope intercept
    6·1 answer
  • I just need answer. Pls
    14·1 answer
  • 80 times 30 plus 60 equals
    7·2 answers
  • If a cable is 50 meters long. How much is that in decimeters?
    13·2 answers
  • Sean and his mom will start running around in one mile track at the same time. Sean runs one mile every 8 minutes his mom runs 1
    7·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!