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grandymaker [24]

3 years ago

11

a jar contains 8 nickels, 10 dimes, 6 quarters, and 22 pennies. a coin is chosen randomly from a jar, what is the probability th

at the coin chosen is a dime?

2 answers:

Rudiy273 years ago

5 0

36/46

I hope that helps!

slega [8]3 years ago

3 0

It would be 5% percent chance a dime

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Help please!!! A bag contains 50 marbles, 10 of which are blue, 8 are red, 20 are green, and 12 are purple. Marcie takes a marbl

Andru [333]

Answer:

A

Step-by-step explanation:

We would need to multiply the number of trials (which is 500) by the probability of choosing a red in 1 try from the information given.

<em>There are 50 in total, and 8 of them are red, so:</em>

P(red) = $\frac{8}{50}=0.16$

<em>Now we multiply this with 500 to get:</em>

$500*0.16=80$

The correct answer is A.

5 0

3 years ago

Read 2 more answers

Maya spent her allowance on playing an arcade game a few times and riding the Ferris wheel more than once.

goldfiish [28.3K]

<span>To write a two-variable equation, you would first need to know how much Mayaâ€™s allowance was. Then, you would need the cost of playing the arcade game and of riding the Ferris wheel. You could let the equation be cost of playing the arcade games plus cost of riding the Ferris wheel equals the total allowance. Your variables would represent the number of times Maya played the arcade game and the number of times she rode the Ferris wheel. With this equation you could solve for how many times she rode the Ferris wheel given the number of times she played the arcade game.</span>

4 0

3 years ago

If an investment of $3000 grows to $4432.37 in eight years with interest compounded annually , what is the interest rate?

melamori03 [73]

$\bf \qquad \textit{Compound Interest Earned Amount}
\\\\
A=P\left(1+\frac{r}{n}\right)^{nt}
\quad 
\begin{cases}
A=\textit{accumulated amount}\to &\$4432.37\\
P=\textit{original amount deposited}\to &\$3000\\
r=rate\to r\%\to \frac{r}{100}\\
n=
\begin{array}{llll}
\textit{times it compounds per year}\\
\textit{annually, thus once}
\end{array}\to &1\\
t=years\to &8
\end{cases}$

$\bf 4432.37=3000\left(1+\frac{r}{1}\right)^{1\cdot 8}\implies \cfrac{4432.37}{3000}=(1+r)^8
\\\\\\
\sqrt[8]{\cfrac{4432.37}{3000}}=1+r\implies \sqrt[8]{\cfrac{4432.37}{3000}}-1=r
\\\\\\
0.0500001086\approx r\qquad\qquad\cfrac{r\%}{100}\approx 0.0500001086
\\\\\\
r\%\approx 100\cdot 0.0500001086\implies r=\stackrel{\%}{5}$

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3 years ago

Can someone help me with this please

zavuch27 [327]

Answer:

8×

Step-by-step explanation:

you just add 7×+1 and the answer will be 8×

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Step-by-step explanation

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2 years ago