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skelet666 [1.2K]
4 years ago
8

Nathaniel writes the general form of the equation gm = cm + rg for when the equation is solved for m. He uses the general form t

o solve the equation –3m = 4m – 15 for m. Which expression shows what Nathaniel will actually evaluate? A. 4 + 15 – 3 B.4 – 15 + 3 C.-15/-3-4 D.–15 – -3/4
Mathematics
2 answers:
Angelina_Jolie [31]4 years ago
8 0

Answer:

The answer is C. I just got it right

Step-by-step explanation:

Snowcat [4.5K]4 years ago
6 0

Answer:

c

Step-by-step explanation:

gm=cm+rg

gm-cm=rg

m(g-c)/g-c = rg/g-c

m=r g/g-c

     -3m=4m-15

-3m-4m=-15

-7m=-15

-15/-7m

= -2.14

-15/-3-4= 2.14

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3 years ago
What are all the values of x, for which the square of x is equal to the value of x increased by 2?
Sedbober [7]
=±22
x
=
±
2
x
2


Using the fact that 2=ln2
2
=
e
ln
⁡
2
:

=±ln22
x
=
±
e
x
ln
⁡
2
2


−ln22=±1
x
e
−
x
ln
⁡
2
2
=
±
1


−ln22−ln22=∓ln22
−
x
ln
⁡
2
2
e
−
x
ln
⁡
2
2
=
∓
ln
⁡
2
2


Here we can apply a function known as the Lambert W function. If =
x
e
x
=
a
, then =()
x
=
W
(
a
)
.

−ln22=(∓ln22)
−
x
ln
⁡
2
2
=
W
(
∓
ln
⁡
2
2
)


=−2(∓ln22)ln2
x
=
−
2
W
(
∓
ln
⁡
2
2
)
ln
⁡
2


For negative values of
x
, ()
W
(
x
)
has 2 real solutions for −−1<<0
−
e
−
1
<
x
<
0
.

−ln22
−
ln
⁡
2
2
satisfies that condition, so we have 3 real solutions overall. One real solution for the positive input, and 2 real solutions for the negative input.

I used python to calculate the values. The dps property is the level of decimal precision, because the mpmath library does arbitrary precision math. For the 3rd output line, the -1 parameter gives us the second real solution for small negative inputs. If you are interested in complex solutions, you can change that second parameter to other integer values. 0 is the default number for that parameter.
8 0
3 years ago
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