Answer:
±5sqrt(2) =x
Step-by-step explanation:
65=15+x^2
Subtract 15 from each side
65-15=15-15+x^2
50 = x^2
Take the square root of each side
±sqrt(50) = sqrt(x^2)
±sqrt(25*2) =x
±sqrt(25)sqrt(2) =x
±5sqrt(2) =x
Answer:
An equation in point-slope form of the line that passes through (-4,1) and (4,3) will be:

Step-by-step explanation:
Given the points
Finding the slope between the points (-4,1) and (4,3)



Refine

Point slope form:

where
- m is the slope of the line
in our case,
substituting the values m = 1/4 and the point (-4,1) in the point slope form of line equation.



Thus, an equation in point-slope form of the line that passes through (-4,1) and (4,3) will be:

Question 1:
Since the triangles are congruent, we know that QS = TV
This means that
3v + 2 = 7v - 6
Subtract both sides by 2
3v = 7v - 8
Subtract 7v from both sides
-4v = -8
Divide both sides by -4
v = 2
Plug this value back into 3v + 2 and you get 8.
QS = 8
Since the triangles are congruent
QS = 8 AND TV = 8
Question 2:
So we know that AC = AC because that's a shared side.
It's also given that BC = CD.
In order for two triangles to be congruent by SAS, the angle between the two sides must be congruent.
That means angle C must be congruent to angle C from the other triangle.
Question 3:
We know that AC = AC because it's a shared side.
We also know that angle A from one triangle is equal to angle C from the other.
However, for a triangle to be congruent by SAS, the congruent angle must be between two congruent sides.
In order for us to prove congruence by SAS, AD must be congruent to BC.
Have an awesome day! :)
The answer is 3.5 & 355 because the decimal shifts to the left or right, you move the decimal in the answer too.
We know that
[area of rectangle]=length*width
area=2g²<span>+34g+140
</span><span>width =2g+14
</span>
step 1
find the roots of 2g²+34g+140
using a graph tool-----> to resolve the second order equation
see the attached figure
the solution is
g=-10
g=-7
so
2g²+34g+140=(2g+14)*(g+10)
therefore
the length is (g+10)
the answer isthe length is (g+10)