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Svetlanka [38]
3 years ago
8

Please Please Please Please Help Please...

Mathematics
1 answer:
nekit [7.7K]3 years ago
5 0

Answer: correct trigonometric ratios

SinB, tanA and cos A.

Step-by-step explanation:

The right triangle has two sides 5 and 12 , by Pythagoras it's hypotenuse is 13.

Tan B=5/12,

Sin A =12/13

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What is 7a+3b+7c please help meeee
trasher [3.6K]

Answer:

I can't help cs it is alredy in simplies form

Step-by-step explanation:

3 0
2 years ago
Match each pair of monomials with their greatest common factor. Tiles 4p4q5 and 8p3q2 24pq6 and 16p3q5 8p3q6 and 4p2q5 16p3q2 an
pashok25 [27]
The GCF of the first two is 4p³q².The GCF of the second two is 8pq⁵.The GCF of the third two is 4p²q⁵.The GCF of the fourth two is 8p²q.The GCF of the fifth two is 4p²q.
To find the GCF of each pair, find the greatest number that will divide into each coefficient.  As for the variable portions, choose the variable that has the smallest exponent from each pair.

8 0
3 years ago
2 (t-4) + 1 math I ready
Roman55 [17]

Answer:

2t-7

Step-by-step explanation:

Not sure what you need ;( hope this helps!

6 0
3 years ago
Read 2 more answers
A game is played with a spinner on a circle, like the minute hand on a clock. The circle is marked evenly from 0 to 100, so, for
zheka24 [161]

Answer:

The probability is 1/2

Step-by-step explanation:

The time a person is given corresponds to a uniform distribution with values between 0 and 100. The mean of this distribution is 0+100/2 = 50 and the variance is (100-0)²/12 = 833.3.

When we take 100 players we are taking 100 independent samples from this same random variable. The mean sample, lets call it X, has equal mean but the variance is equal to the variance divided by the length of the sample, hence it is 833.3/100 = 8.333.

As a consecuence of the Central Limit Theorem, the mean sample (taken from independant identically distributed random variables) has distribution Normal with parameters μ = 50, σ= 8.333. We take the standarization of X, calling it W, whose distribution is Normal Standard, in other words

W = \frac{X - \mu}{\sigma} = \frac{X - 50}{8.333} \simeq N(0,1)

The values of the cummulative distribution of the Standard Normal distribution, lets denote it \phi , are tabulated and they can be found in the attached file, We want to know when X is above 50, we can solve that by using the standarization

P(X > 50) = P(\frac{X-50}{8.33} > \frac{50-50}{8.33}) = P(W > 0) = \phi(0) = 1/2

Download pdf
8 0
3 years ago
I need help with this i don’t understand
Phoenix [80]

Answer:

15

measure of third side is = 25^2 - 20^2

= 625 - 400

= 225

= √225

= 15

hope it helps

7 0
3 years ago
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