Hello AljakeVillena!

You pull horizontally on a 50-kg crate with a force of 450 n and the friction force on the crate is 250 n. the acceleration of the crate is ?

Given,
- mass of crate = 50 kg
- Force you pull it with = 450 N
- Frictional force = 250 N
- Acceleration = ?
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Let's first find the total force/net force acting on the crate. The total force will be :-
- 450 N - 250 N = <u>2</u><u>0</u><u>0</u><u> </u><u>N.</u>
We subtracted the forces because both the forces act on opposite directions.
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Now, let's find the acceleration of the crate. To find the acceleration we must divide the net force by the mass. So,..
- Acceleration = Force/mass
- a = F/m
- a = 200/50
- <u>a = 4 m/s²</u>
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So, the acceleration of the crate is <u>4</u><u> </u><u>m/</u><u>s²</u><u>.</u>
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Hope it'll help you!
ℓu¢αzz ッ
The angle x is complimentary to the given angle
Therefore x = 90-29 = 61 degrees
Answer:
7:6
Step-by-step explanation:
Dalmatian: 72
Bullmastiff: 72 + 24
= 96
Bulldog: 96 - 12
= 84
Bulldog : Dalmatian
84 : 72
^ Simplify
7 : 6
Answer:
Image?
Step-by-step explanation:
What is this supposed to be? Is there any actual question?