Answer:
This problem is incomplete, we do not know the fraction of the students that have a dog and also have a cat. Suppose we write the problem as:
"In Mrs.Hu's classroom, 4/5 of the students have a dog as a pet. X of the students who have a dog as a pet also have cat as a pet. If there are 45 students in her class, how many have both a dog and a cat as pets?"
Where X must be a positive number smaller than one, now we can solve it:
we know that in the class we have 45 students, and 4/5 of those students have dogs, so the number of students that have a dog as a pet is:
N = 45*(4/5) = 36
And we know that X of those 36 students also have a cat, so the number of students that have a dog and a cat is:
M = 36*X
now, we do not have, suppose that the value of X is 1/2 ("1/2 of the students who have a dog also have a cat")
M = 36*(1/2) = 18
So you can replace the value of X in the equation and find the number of students that have a dog and a cat as pets.
Answer:
y greater . ...3x-9
Step-by-step explanation:
The volume of soup in the cylindrical can is 100.48 inches cube.
<h3>How to find the volume of a cylindrical can?</h3>
We have to find the volume of the soup in a cylindrical can of height 8 inches and 4 inches across the lid.
The volume of the soup is the volume of the cylindrical can.
Therefore,
volume of the cylindrical can = πr²h
where
- r = radius of the cylinder
- h = height of the cylinder
Therefore,
h = 8 inches
r = 4 / 2 = 2 inches
volume of the soup in the cylindrical can = πr²h
volume of the soup in the cylindrical can = π × 2² × 8
volume of the soup in the cylindrical can = π × 4 × 8
volume of the soup in the cylindrical can = 32π
Therefore,
volume of the soup in the cylindrical can = 32 × 3.14
volume of the soup in the cylindrical can = 100.48 inches³
learn more on volume here:brainly.com/question/23207959
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Answer:
a & d
Step-by-step explanation:
got them right om edge
Answer: -0.57
Step-by-step explanation:
z-score: data - mean / standard deviation
25 - 27 / 3.5
= -0.57
