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steposvetlana [31]
3 years ago
11

Find limit as x approaches -3- of x/(sqrt(x^2-9)

Mathematics
1 answer:
gregori [183]3 years ago
5 0
lim_{x \rightarrow -3} \frac{x}{x^2-9} =lim_{x \rightarrow -3} \frac{1}{2x} = \frac{1}{2(-3)} =- \frac{1}{6}
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