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3 years ago

Find limit as x approaches -3- of x/(sqrt(x^2-9)

Mathematics

1 answer:

gregori [183]3 years ago

5 0

$lim_{x \rightarrow -3} \frac{x}{x^2-9} =lim_{x \rightarrow -3} \frac{1}{2x} = \frac{1}{2(-3)} =- \frac{1}{6}$

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A screening test wished to improve the diagnostic ability to identify Zika-infected fetuses in pregnancy rather than after birth

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Answer:

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3 years ago

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Answer:

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2 years ago

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iren2701 [21]

Answer: The correct answer is: " 3 " .

_______________________________

Step-by-step explanation:

_______________________________

The problem given is:

_______________________________

Evaluate: log 2 base 8 .

_______________________________

Rewrite as: " $log_2}8 = ? _______________$ " ; $log_2}8 = ? _______________$

_______________________

Take note of the following definition of a logarithm:

_______________________

" $log_{m}n = a$ " ; ↔ " $m^{a} =n$ " ;

_______________________

in which: $m$ refers to the "base" ;

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As such:

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Note:

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___________________

→ " $2^{x} = 8$ " ;

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Thus:

"log 2 base 8 " ;

= $log{_{2}}8 = 3$ .

_______________________

Hope this helps!

Best wishes to you!

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3 years ago