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Lerok [7]
3 years ago
15

Please help will give brainlist

Mathematics
2 answers:
SpyIntel [72]3 years ago
4 0
6(x²-4x+4-4)+1=0, 6(x-2)²-24+1=0, 6(x-2)²=23, x-2=±√(23/6), x=2±√(23/6)=2±1.95789, so x=3.95789 or 0.04211 approx. These are the zeroes.
baherus [9]3 years ago
4 0

Answer:

Option D. x=2+\sqrt{\frac{23}{6}},2-\sqrt{\frac{23}{6}}

Step-by-step explanation:

The given function is f(x) = 6x² - 24x + 1

The zeros of the given quadratic function can be calculated by quadratic formula

x=\frac{-b\pm \sqrt{b^{2}-4ac}}{2a}

By putting values a = 6, b = -24, c = 1 in the quadratic formula

x=\frac{24\pm \sqrt{(-24))^{2}-4(6)(1)}}{2(6)}=\frac{24\pm \sqrt{576-24}}{12}=\frac{24\pm \sqrt{552}}{12}=2\pm \sqrt{\frac{552}{144}}=2\pm \sqrt{\frac{23}{6}}

x=(2+\sqrt{\frac{23}{6}}),(2-\sqrt{\frac{23}{6}})

Option D. is the correct option.

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