Question

Please help will give brainlist

Answer 1

6(x²-4x+4-4)+1=0, 6(x-2)²-24+1=0, 6(x-2)²=23, x-2=±√(23/6), x=2±√(23/6)=2±1.95789, so x=3.95789 or 0.04211 approx. These are the zeroes.

Answer 2

Answer:

Option D. $x=2+\sqrt{\frac{23}{6}},2-\sqrt{\frac{23}{6}}$

Step-by-step explanation:

The given function is f(x) = 6x² - 24x + 1

The zeros of the given quadratic function can be calculated by quadratic formula

$x=\frac{-b\pm \sqrt{b^{2}-4ac}}{2a}$

By putting values a = 6, b = -24, c = 1 in the quadratic formula

$x=\frac{24\pm \sqrt{(-24))^{2}-4(6)(1)}}{2(6)}=\frac{24\pm \sqrt{576-24}}{12}=\frac{24\pm \sqrt{552}}{12}=2\pm \sqrt{\frac{552}{144}}=2\pm \sqrt{\frac{23}{6}}$

$x=(2+\sqrt{\frac{23}{6}}),(2-\sqrt{\frac{23}{6}})$

Option D. is the correct option.