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Lerok [7]
3 years ago
15

Please help will give brainlist

Mathematics
2 answers:
SpyIntel [72]3 years ago
4 0
6(x²-4x+4-4)+1=0, 6(x-2)²-24+1=0, 6(x-2)²=23, x-2=±√(23/6), x=2±√(23/6)=2±1.95789, so x=3.95789 or 0.04211 approx. These are the zeroes.
baherus [9]3 years ago
4 0

Answer:

Option D. x=2+\sqrt{\frac{23}{6}},2-\sqrt{\frac{23}{6}}

Step-by-step explanation:

The given function is f(x) = 6x² - 24x + 1

The zeros of the given quadratic function can be calculated by quadratic formula

x=\frac{-b\pm \sqrt{b^{2}-4ac}}{2a}

By putting values a = 6, b = -24, c = 1 in the quadratic formula

x=\frac{24\pm \sqrt{(-24))^{2}-4(6)(1)}}{2(6)}=\frac{24\pm \sqrt{576-24}}{12}=\frac{24\pm \sqrt{552}}{12}=2\pm \sqrt{\frac{552}{144}}=2\pm \sqrt{\frac{23}{6}}

x=(2+\sqrt{\frac{23}{6}}),(2-\sqrt{\frac{23}{6}})

Option D. is the correct option.

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Answer:

1) The mean calculated for this case is \bar X=61.5

2)  61.5-5.4=56.1

3) 61.5+5.4=66.9

4) B. An interval estimate gives us a sense of the accuracy of the point estimate whereas a point estimate alone does not.

Because with the confidence interval we know the confidence level of the interval, and the limits for the parameter at some significance level.  

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

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Part 1

In order to calculate the mean and the sample deviation we can use the following formulas:  

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s=\sqrt{\frac{\sum_{i=1}^n (x_i-\bar X)}{n-1}} (b)  

The mean calculated for this case is \bar X=61.5

The sample deviation calculated s=5.143

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Part 2

The confidence interval for the mean is given by the following formula:

\bar X \pm ME   (1)

So if we have the margin of error 5.4mm we can find the lowr limit like this:

61.5-5.4=56.1

Part 3

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Part 4

B. An interval estimate gives us a sense of the accuracy of the point estimate whereas a point estimate alone does not.

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Answer:

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