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raketka [301]
3 years ago
11

Given 7, 9, and 11 as the three sides of a triangle, classify it as one of the

Mathematics
1 answer:
dusya [7]3 years ago
7 0
The triangle would be acute
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Point T is the midpoint of JH. The coordinate of T is (0, 5) and the coordinate of J is (0, 2). The coordinate of H is:
aev [14]
\bf ~~~~~~~~~~~~\textit{middle point of 2 points }\\\\
\begin{array}{ccccccccc}
&&x_1&&y_1&&x_2&&y_2\\
%  (a,b)
&J&(~ 0 &,& 2~) 
%  (c,d)
&H&(~ x &,& y~)
\end{array}\qquad
%   coordinates of midpoint 
\left(\cfrac{ x_2 +  x_1}{2}\quad ,\quad \cfrac{ y_2 +  y_1}{2} \right)
\\\\\\
\left(\cfrac{x+0}{2}~~,~~\cfrac{y+2}{2}  \right)=\stackrel{midpoint~T}{(0~,~5)}\implies 
\begin{cases}
\cfrac{x+0}{2}=0\\\\
\boxed{x=0}\\
------\\
\cfrac{y+2}{2}=5\\\\
y+2=10\\
\boxed{y=8}
\end{cases}
6 0
3 years ago
Match the pairs of equations that represent concentric circles. Tiles
Darina [25.2K]
I will explain you and pair two of the equations as an example to you. Then, you must pair the others.

1) Two circles are concentric if they have the same center and different radii.

2) The equation of a circle with center xc, yc, and radius r is:

(x - xc)^2 + (y - yc)^2 = r^2.

So, if you have that equation you can inmediately tell the coordinates of the center and the radius of the circle.

3) You can transform the equations given in your picture to the form (x -xc)^2 + (y -yc)^2 = r2 by completing squares.

Example:

Equation: 3x^2 + 3y^2 + 12x - 6y - 21 = 0

rearrange: 3x^2 + 12x + 3y^2 - 6y = 21

extract common factor 3: 3 (x^2 + 4x) + 3(y^2 -2y) = 3*7

=> (x^2 + 4x) + (y^2 - 2y) = 7

complete squares: (x + 2)^2 - 4 + (y - 1)^2 - 1 = 7

=> (x + 2)^2 + (y - 1)^2 = 12 => center = (-2,1), r = √12.

equation: 4x^2 + 4y^2 + 16x - 8y - 308 = 0

rearrange: 4x^2 + 16x + 4y^2 - 8y = 308

common factor 4: 4 (x^2 + 4x) + 4(y^2 -8y) = 4*77

=> (x^2 + 4x) + (y^2 - 2y) = 77

complete squares: (x + 2)^2  - 4 + (y - 1)^2 - 1 = 77

=> (x + 2)^2 + (y - 1)^2 = 82 => center = (-2,1), r = √82

Therefore, you conclude that these two circumferences have the same center and differet r, so they are concentric.
5 0
3 years ago
The sphere area of a sphere is 200.96 square centimeters. What is the approximate volume of the sphere? Use 3.14 for pi. Round y
julsineya [31]

We are given

area of sphere is 200.96cm^2

it means that we are given surface area

so, we can use surface area formula

S=4\pi r^2

where S is surface area

r is radius

so, firstly we need to find radius or r

200.96=4\pi r^2

we can solve for r

r=3.9989cm

now, we can find volume

V=\frac{4}{3} \pi r^3

we can plug r

V=\frac{4}{3} \pi (3.9989)^3

now, we can find volume

V=267.86cm^3.............Answer

7 0
3 years ago
With a line 7 cm long. Use a set square and a ruler and draw perpendicular lines at both ends
Setler79 [48]

Answer:

See Explanation

Step-by-step explanation:

According to the Question,

Steps of construction:

  • Step I - Draw a line segment AB = 7 cm with the help ruler.
  • Step II - with vertex A, by using compass take more than half of AB and draw arcs, one on each side of AB.
  • Step III - with vertex B, by using a compass with the same length, cut the previous arcs at X and Y respectively.
  • Step IV - with help of the ruler join the points X and Y Thus XY is the perpendicular bisector of line AB.

(For Diagram please find in attachment)

5 0
2 years ago
It’s a test I need a answer fast
Sloan [31]

Answer:

.

Step-by-step explanation:test

5 0
2 years ago
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