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xz_007 [3.2K]
3 years ago
7

What is the value of 2-2x-3y5 for x = 2 and y = -4?

Mathematics
1 answer:
a_sh-v [17]3 years ago
6 0
2 - 2(2) - 3(-4)5
2 - 4 + 60 = 58
The answer is 58
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A scientist measures the distance, in feet, between animals and the surface of a pond.
aleksandr82 [10.1K]

Considering the opposite of the rational number -1/2, the location of the snail is represented by the number 1/2.

<h3>What is the missing information?</h3>

This problem is incomplete, but researching it on a search engine, we have that:

  • The fish is located at -1/2 feet.
  • The snail is located at the opposite location of the fish.

<h3>What is the opposite of a rational number?</h3>

The opposite of a rational number a is given by -a, that is, it is the number with the opposite signal.

Hence, the <u>opposite of -1/2 is 1/2</u>, and the location of the snail is represented by the number 1/2.

More can be learned about rational numbers at brainly.com/question/13325494

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4 0
1 year ago
Find the polynomial of minimum degree, with real coefficients, zeros at
drek231 [11]

Answer:

\huge\boxed{p(x)=4x^3-20x^2+4x+300}

Step-by-step explanation:

\text{If}\ x=4\pm3i\ \text{and}\ x=-3\ \text{are the zeros of a polynomial, then it has  a form:}\\\\p(x)=\bigg(x-(4-3i)\bigg)\bigg(x-(4+3i)\bigg)\bigg(x-(-3)\bigg)\bigg(r(x)\bigg)\\\\p(x)=(x-4+3i)(x-4-3i)(x+3)\bigg(r(x)\bigg)\\\\p(x)=\underbrace{\bigg((x-4)+3i\bigg)\bigg((x-4)-3i\bigg)}_{\text{use}\ (a+b)(a-b)=a^2-b^2}(x+3)\bigg(r(x)\bigg)\\\\p(x)=\bigg((x-4)^2-(3i)^2\bigg)(x+3)\bigg(r(x)\bigg)\qquad\text{use}\ (a-b)^2=a^2-2ab+b^2

p(x)=(x^2-2(x)(4)+4^2-3^2i^2)(x+3)\bigg(r(x)\bigg)\qquad\text{use}\ i^2=-1\\\\p(x)=(x^2-8x+16-9(-1))(x+3)\bigg(r(x)\bigg)\\\\p(x)=(x^2-8x+16+9)(x+3)\bigg(r(x)\bigg)\\\\p(x)=(x^2-8x+25)(x+3)\bigg(r(x)\bigg)\qquad\text{use FOIL}:\ (a+b)(c+d)=ac+ad+bc+bd\\\\p(x)=\bigg((x^2)(x)+(x^2)(3)+(-8x)(x)+(-8x)(3)+(25)(x)+(25)(3)\bigg)\bigg(r(x)\bigg)\\\\p(x)=(x^3+3x^2-8x^2-24x+25x+75)\bigg(r(x)\bigg)\qquad\text{combine like terms}\\\\p(x)=(x^3-5x^2+x+75)\bigg(r(x)\bigg)

\text{The y-intercept is at 300}.\\\\\text{For}\ w(x)=a_nx^n+a_{n-1}x^{n-1}+a_{n-2}x^{n-2}+...+a_1x+a_0\\\\\text{y-intercept is}\ a_0\\\\\text{Therefore for}\ p(x)=(x^3-5x^2+x+75)\bigg(r(x)\bigg)\\\\\text{y-intercet is}\ 75\bigg(r(x)\bigg)\\\\75\bigg(r(x)\bigg)=300\qquad\text{divide both sides by 75}\\\\r(x)=4\\\\\text{Finally:}\\\\p(x)=(x^3-5x^2+x+75)(4)\qquad\text{use the distributive property}\\\\p(x)=(x^3)(4)+(-5x^2)(4)+(x)(4)+(75)(4)\\\\p(x)=4x^3-20x^2+4x+300

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Alex17521 [72]

Answer: ok so meep is gunna meep to the meep power of meep and 6 more meeps

Step-by-step explanation:

i got it right when i looked it up lol

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How do I solve 2f+10?
Scorpion4ik [409]
First of all, you want the variable to be isolated, so in order to do that, you divide in both sides. Ten divided by two is five. So f = 5.

2f + 10
---    ---
2      2

10 divided by 2 = 5
5 0
3 years ago
Read 2 more answers
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