<h3>
Answer: SAS</h3>
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How to get this answer:
We're told that AD = BC, so that is one pair of sides that are congruent. This forms the first "S" in "SAS"
The "A" refers to the congruent angles, which happen to be angle DAB and angle CBA, both are 90 degrees
The second "S" in "SAS" is the second pair of congruent sides. Those two sides are the overlapping shared side of AB. It might help to peel the two triangles apart to get a better look.
Note how the angles are between the two pairs of sides mentioned.
Answer:
The dog will run the 21-mile race in 4.04 hours
Step-by-step explanation:
The first thing we need to do is find out how far he ran the race at the local fair in 1 hour.
To do this, we can set up a simple relationship:
If he ran 10.5 miles in 2 hours,
He will run x miles in 1 hour
Cross multiplying, we have
x = (10.5 X 1)/2 = 5.25 miles in 1 hour.
We can now comfortably say that he runs at the rate of 5.2miles/hr
He now goes to the state fair race, which is 21 miles long.
if he runs at the rate of 5.2 miles in 1 hour,
He will run 21 miles in y hours
y = 21 / 5.2 = 4.04 hours
The dog will run the 21-mile race in 4.04 hours
Answer:
i dont know sry need points sry
Step-by-step explanation:
(r,theta) represents polar coordinate .
And in (r,theta), there is neither any restriction on r nor on theta. It means both r and theta can either be positive or negative .
For e.g. (2,30 degree), (2,-30 degree) both are correct .
So the given statement is true .
Let's begin by listing the first few multiples of 4: 4, 8, 12, 16, 20, 24, 28, 32, 36, 38, 40, 44. So, between 1 and 37 there are 9 such multiples: {4, 8, 12, 16, 20, 24, 28, 32, 36}. Note that 4 divided into 36 is 9.
Let's experiment by modifying the given problem a bit, for the purpose of discovering any pattern that may exist:
<span>How many multiples of 4 are there in {n; 37< n <101}? We could list and then count them: {40, 44, 48, 52, 56, 60, 64, 68, 72, 76, 80, 84, 88, 92, 96, 100}; there are 16 such multiples in that particular interval. Try subtracting 40 from 100; we get 60. Dividing 60 by 4, we get 15, which is 1 less than 16. So it seems that if we subtract 40 from 1000 and divide the result by 4, and then add 1, we get the number of multiples of 4 between 37 and 1001:
1000
-40
-------
960
Dividing this by 4, we get 240. Adding 1, we get 241.
Finally, subtract 9 from 241: We get 232.
There are 232 multiples of 4 between 37 and 1001.
Can you think of a more straightforward method of determining this number? </span>
