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jek_recluse [69]
3 years ago
11

An airplane is flying at an altitude of 10,000 ft. The airport at which it is scheduled to land is 50 miles away. Find the avera

ge angle at which the airplane must descend for landing. Round your answer to the nearest degree.
Mathematics
1 answer:
Vinil7 [7]3 years ago
3 0

Answer:

The average angle at which the airplane must descend for landing is 21°

Step-by-step explanation:

Here, we have question related to angle of elevation and depression

The height of the airplane be, y = 10,000 ft

The Location of the airport is, x  =  50 miles = ‪26400 ‬ft

Therefore,

we have,

Let the average angle be θ

Therefore,

tan \theta = \frac{y}{x} = \frac{Opposite}{Adjacent}

The opposite to the angle of descent is the height and the adjacent is the distance of the airport away from the airplane

Therefore, tan θ = \frac{10000}{26400} = 0.379

Therefore, the average angle θ = tan⁻¹ 0.379 = 20.746 ° ≈ 21°.

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snow_lady [41]

Answer:

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Step-by-step explanation:

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i got that by adding all the number out which equal too =2,650

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After some trial and error i found it

so you add 494+690+502+478+486+542=3,192

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Aleksandr-060686 [28]

Hello!

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Answer:

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Answer:

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Step-by-step explanation:

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