What is the sum of (2.14x+3.7)+(5+4.9x)?

Assume that a chocolate bar consists of n squares arranged in a rectangular pattern. The entire bar, a smaller rectangularpieceo

motikmotik

Step-by-step explanation:

Claim:

it takes n - 1 number of breaks to break the bar into n separate squares for all integers n.

Basic case -> n = 1

The bar is already completely broken into pieces.

Case -> n ≥ 2

Assuming that assertion is true for all rectangular bars with fewer than n squares. Break the bar into two pieces of size k and n - k where 1 ≤ k < n

The bar with k squares requires k − 1 breaks and the bar with n − k squares

requires n − k − 1 breaks.

So the original bar requires 1 + (k−1) + (n−k−1) breaks.

simplifying yields,

1 + k − 1 + n − k − 1

1 - 1 + n - 1

n - 1

Therefore, we proved as we claimed that it takes n - 1 breaks to break the bar into n separate squares.

8 0

3 years ago

Precizează felul atributelor din enunțurile de mai jos, analizând părțile de vorbire prin care se exprimă.

Llana [10]

Answer:

Step-by-step explanation:

Dorința de a mă juca este mare.

de a (mă) juca - atribut verbal (care dorință?) exprimat prin verb la modul infinitiv;

Avea aerul a nu înțelege.

a nu înțelege - atribut verbal (ce fel de aer?) exprimat prin verb la modul infinitiv;

El dovedise un curaj de invidiat.

de invidiat - atribut verbal (ce fel de curaj?), exprimat prin verb la modul supin.

Casele aveau coșuri fumegânde.

fumegânde - atribut adjectival, exprimat prin verb la gerunziu acordat (cu valoare adjectivală)

Nevoia de a o lua din de a o lua dinloc din cauza frigului era mare.

de a o lua din loc - atribut verbal, exprimat prin locuțiune verbală la modul infinitiv;

A lipi bileţele pe un frigider este un mijloc de adus aminte.

de adus aminte - atribut verbal, exprimat prin locuțiune verbală la modul supin;

Fata ținând nasul pe sus a alunecat pe gheață.

ținând nasul pe sus - atribut verbal, exprimat prin locuțiune verbală la modul gerunziu (neacordat);

Blocul de acolo este înalt.

de acolo - atribut adverbial, exprimat prin adverb de loc;

Trezitul devreme nu-mi place.

devreme - atribut adverbial, exprimat prin adverb de timp;

Mersul de colo până colo l-a obosit.

de colo până colo - atribut adverbial exprimat prin locuțiune adverbială;

E o vreme brrr!

brrr - atribut interjecțional, exprimat prin interjecție.

8 0

3 years ago

Kyle bought a DVD that cost $19.23, including tax. She gave the sales clerk a $20 bill. How much change should Kyle receive?

maxonik [38]

Answer: Kyle received $0.77

Step-by-step explanation:

6 0

3 years ago

Read 2 more answers

Which number should follow in this series: 64/64 9/12 6/12

zheka24 [161]

Answer: $\frac{1}{4}$

Step-by-step explanation:

You can reduce the fractions, then:

$\frac{64}{64}=1$

$\frac{9}{12}=\frac{3}{4}$

$\frac{6}{12}=\frac{3}{6}=\frac{1}{2}$

Rewrite them as following:

$1,\frac{3}{4},\frac{1}{2}$

If you subtract the first number and the second number, you obtain:

$1-\frac{3}{4}=\frac{1}{4}$

If you subtract the second number and the second number, you obtain:

$\frac{3}{4}-\frac{1}{2}=\frac{1}{4}$

Therefore, you must subtract $\frac{1}{2}$ and $\frac{1}{4}$ to obtain the number asked. Then, this is:

$\frac{1}{2}-\frac{1}{4}=\frac{1}{4}$

6 0

3 years ago

Read 2 more answers

Use the cumulative normal distribution table to find the z-scores thqt bound the middle of 68% of theje area under the stanrard

padilas [110]

Answer:

Z scores between -0.995 and 0.995 bound the middle 68% of the area under the stanrard normal curve

Step-by-step explanation:

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the z-score of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

Middle 68%

Between the 50 - (68/2) = 16th percentile and the 50 + (68/2) = 84th percentile.

16th percentile:

X when Z has a pvalue of 0.16. So X when Z = -0.995

84th percentile:

X when Z has a pvalue of 0.84. So X when Z = 0.995.

Z scores between -0.995 and 0.995 bound the middle 68% of the area under the stanrard normal curve

7 0

3 years ago