Answer:d) Mono-alphabetic substitution rules
Explanation: Poly-alphabetic cipher is the cryptography that is done by using the many alphabets in substitutional way. They are supposed to have a good security because they use cipher text alphabets for the encryption and then decrypts it.
Substitution of the alphabets is done by the rule of the mono-alphabetic substitution rules.Other given options are incorrect because they are not used in the cryptography of the alphabetic cipher. Thus option (d) is the correct answer.
Answer:
a parameter is fixed over time, while an exogenous variable is allowed to change over time.
Explanation:
A parameter can be defined as a value that can be passed to a function. Thus, a parameter refers to a value that must be passed into a function, subroutine or procedure when it is called.
This value can be passed to a function either by reference or by value.
Basically, parameters can serve as a model for a function; when used as an input, such as for passing a value to a function and when used as an output, such as for retrieving a value from the same function.
A variable can be defined as a placeholder or container for holding a piece of information that can be modified or edited. Thus, a variable stores information which is passed from the location of the method call directly to the method that is called by the program.
An exogenous variable can be defined as a that's independent of other variables in a system i.e it's not affected by other variables.
This ultimately implies that, the difference between a parameter and an exogenous variable is that a parameter is fixed over time, while an exogenous variable is allowed to change over time and as such it has a relationship with other variables in a system.
CVP Chart.
Source: "New Perspectives on Microsoft Excel 2010: Comprehensive" by June Parsons, Dan Oja, Roy Ageloff, Patrick Carey.
Hello astropiggy!
Feel free to ask any question!
I’ll try my best to answer them!
import java.util.Scanner;
public class JavaApplication42 {
public static void main(String[] args) {
Scanner scan = new Scanner(System.in);
int count = 0;
System.out.println("Enter an integer between 0 and 100");
int num = scan.nextInt();
if (num <= 0 || num >= 100){
System.out.println("error");
}
else{
while(num <= 100){
if (count == 20){
System.out.println("");
count = 0;
}
else{
System.out.print(num+" ");
count++;
num++;
}
}
}
}
}
I hope this helps!
