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ira [324]
3 years ago
14

Write modified code that will generate a random number between 0 and 255 when a button is pressed and will write the number to t

he serial monitor as well as to the receiver Arduino.
Computers and Technology
1 answer:
kobusy [5.1K]3 years ago
8 0

Solution :

#include<LiquidCrystal.h>

int value;

int flag;

LiquidCrystal lcd(12, 11, 5, 4, 3, 2);

void setup()

{

lcd.begin(16, 2);

Serial.begin(9600);

}

void loop()

{

value=digitalRead(7);

  if(value==0){

flag=1;}

  if(value==1){

flag=~flag;}

  if (flag==1){

lcd.setCursor(0,0);    

  lcd.print("number is");

lcd.setCursor(2,1);    

lcd.print(random(0, 255));

delay(1000);

}

  else{

lcd.setCursor(0,0);

lcd.print("Not Pressed");

delay(1000);

lcd.clear();}

}

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Use the STL class vector to write a C function that returns true if there are two elements of the vector for which their product
Tema [17]

Answer:

Code is provided in the attachment form

Explanation:

Vector Multiplication code:

Vector_multiplication.c file contains C code.

See attachment no 1 attached below

Classification of Algorithm: For creating elements in vector c of size n, number of scalar  multiplications is equal to n. The size of original two vectors scales directly with the number of  operations. Hence, it is classified as O(n).

7 0
3 years ago
1. Print out the string length of s1 2. Loop through characters in s2 with charAt() and display reversed string 3. Compare s2, s
konstantin123 [22]

Answer:

See explaination

Explanation:

public class StringLab9 {

public static void main(String args[]) {

char charArray[] = { 'C', 'O', 'S', 'C', ' ', '3', '3', '1', '7', ' ', 'O', 'O', ' ', 'C', 'l', 'a', 's', 's' };

String s1 = new String("Objected oriented programming language!");

String s2 = "COSC 3317 OO class class";

String s3 = new String(charArray);

// To do 1: print out the string length of s1

System.out.println(s1.length());

// To do 2: loop through characters in s2 with charAt and display reversed

// string

for (int i = s2.length() - 1; i >= 0; --i)

System.out.print(s2.charAt(i));

System.out.println();

// To do 3: compare s2, s3 with compareTo(), print out which string (s2 or s3)

// is

// greater than which string (s2 or s3), or equal, print the result out

if (s2.compareTo(s3) == 0)

System.out.println("They are equal");

else if (s2.compareTo(s3) > 0)

System.out.println("s2 is greater");

else

System.out.println("s3 is greater");

// To do 4: Use the regionMatches to compare s2 and s3 with case sensitivity of

// the first 8 characters.

// and print out the result (match or not) .

if (s2.substring(0, 8).compareTo(s3.substring(0, 8)) == 0)

System.out.println("They matched");

else

System.out.println("They DONT match");

// To do 5: Find the location of the first character 'g' in s1, print it out

int i;

for (i = 0; i < s2.length(); ++i)

if(s2.charAt(i)=='g')

break;

System.out.println("'g' is present at index " + i);

// To do 6: Find the last location of the substring "class" from s2, print it

// out

int index = 0, ans = 0;

String test = s2;

while (index != -1) {

ans = ans + index;

index = test.indexOf("class");

test = test.substring(index + 1, test.length());

}

System.out.println("Last location of class in s2 is: " + (ans + 1));

// To do 7: Extract a substring from index 4 up to, but not including 8 from

// s3, print it out

System.out.println(s3.substring(4, 8));

} // end main

} // end class StringLab9

7 0
3 years ago
Which device protects computer systems from voltage fluctuations?
meriva
A fuse protects computer system from voltage fluctuations
6 0
3 years ago
Read 2 more answers
Which of the following is NOT a career in the Information Support and Services pathway?
frosja888 [35]

Answer:

here yuuuurrrrr Vote for me nah jk

6 0
2 years ago
Wikis are designed for ________, which is allowing people to contribute more than just posting a response
Viefleur [7K]

Answer:

collabirations

Explanation

Wikis are designed for collabirations, which is allowing people to contribute more than just posting a response.

4 0
3 years ago
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