What is 363.3 times 3456.2

I’ll give brainliest! Please it’s already missing

Lyrx [107]

<h2>Answer:-</h2>

$\pink{\bigstar}$ Amount of apple juice Will added $\large\leadsto\boxed{\tt\purple{1 \frac{5}{12}}}$

<h3>• Given:-</h3>

Will puts 1/4 cup of grape juice in a cup.
He added apple juice and then he had 1⅔ cup of juice in the cup.

How much apple juice Will added to the cup?

<h3>• Solution:-</h3>

➪ Amount of grape juice Will added = 1/4

➪ Amount of juice in total after adding the apple juice = 1⅔

Therefore, it is clear that the amount of apple juice Will added to the cup will be the difference in total amount of juice and amount of grape juice.

Hence,

➪ $\sf 1 \frac{2}{3} - \dfrac{1}{4}$

➪ $\sf \dfrac{5}{3} - \dfrac{1}{4}$

• Taking an L.CM:-

➪ $\sf \dfrac{20 - 3}{12}$

➪ $\sf \dfrac{17}{12}$

➪ $\large{\bold\red{1 \frac{5}{12}}}$

Therefore, the amount of apple juice added is $\large{\bold 1 \frac{5}{12}}$

4 0

3 years ago

Help me please please please

Digiron [165]

Answer:

GPA ≈ 2.67

Step-by-step explanation:

Grade points are weighted by credit hours:

GPA = ∑(grade points×credit hours) / ∑(credit hours)

GPA = (3×2 +2×4 +4×3 +2×3)/(2 +4 +3 +3)

= (6 +8 +12 +6)/12 = 32/12 = 2 2/3

GPA ≈ 2.67

3 0

2 years ago

The measurements of 11 fish caught during an angling competition are recorded.

stepladder [879]

Answer:

Step-by-step explanation:

A) = (35,?)

B) = POSITIVE

C) = 601

7 0

3 years ago

Given GHI G (4,-3), H (-4,2), and I (2,4), find the perpendicular bisector of HI in standard form.

Olin [163]

Answer:

$3x+y=0$

Step-by-step explanation:

step 1

Find the slope of segment HI

The formula to calculate the slope between two points is equal to

$m=\frac{y2-y1}{x2-x1}$

we have

H (-4,2), and I (2,4)

substitute the given points

$m=\frac{4-2}{2+4}$

$m=\frac{2}{6}$

simplify

$m=\frac{1}{3}$

step 2

Find the slope of the perpendicular line to segment HI

we know that

If two lines are perpendicular, then their slopes are opposite reciprocal (the product of their slopes is equal to -1)

$m_1*m_2=-1$

we have

$m_1=\frac{1}{3}$

so

$m_2=-3$

step 3

Find the midpoint segment HI

we know that

The formula to calculate the midpoint between two points is equal to

$M(\frac{x1+x2}{2},\frac{y1+y2}{2})$

we have

H (-4,2), and I (2,4)

substitute

$M(\frac{-4+2}{2},\frac{2+4}{2})$

$M(-1,3)$

step 4

we know that

The perpendicular bisector of HI is a line perpendicular to HI that passes though the midpoint of HI

Find the equation of the perpendicular bisector of HI in point slope form

$y-y1=m(x-x1)$

we have

$m=-3$

$M(-1,3)$

substitute

$y-3=-3(x+1)$

step 5

Convert to slope intercept form

$y=mx+b$

Isolate the variable y

$y-3=-3x-3$

$y=-3x-3+3$

$y=-3x$

step 6

Convert to standard form

$Ax+By=C$

where

A is a positive integer

B and C are integers

$y=-3x$

Adds 3x both sides

$3x+y=0$

see the attached figure to better understand the problem

3 0

4 years ago

I'm blanking on how to do this, I learned it so long ago, any help would be greatly appreciated. More interested on how to do it

anyanavicka [17]

Answer:

$\dfrac{16 y^{22}}{x^{10}z^{10}}$

Step-by-step explanation:

Given expression is ,

$\sf\longrightarrow \bigg(\dfrac{2x^3y^{-5}z^8}{8x^{-2}y^6z^3}\bigg)^{-2}$

This would be simplified using the law of exponents , some of which I will use here are ,

$(an)^m = a^m n^m$
$\dfrac{a^m}{a^n}=a^{m-n}$

$a^m a^n = a^{m+n}$
$a^{-n} = \dfrac{1}{a^n}$

Using the above laws ,

$\sf \longrightarrow \bigg[ \dfrac{2}{8} \bigg(\dfrac{x^3}{x^{-2}}\bigg)\bigg(\dfrac{y^{-5}}{y^6}\bigg)\bigg(\dfrac{z^8}{z^3}\bigg) \bigg]^{-2}$

Using the second law mentioned above , we have,

$\sf \longrightarrow \bigg[ \dfrac{1}{4}(x^{3+2})(y^{-5-6})(z^{8-3})\bigg]^{-2}$

Simplify ,

$\sf \longrightarrow \bigg[\dfrac{1}{4} x^5y^{-11}z^5\bigg]^{-2}$

Using the first law mentioned above , we have,

$\sf \longrightarrow \bigg[ \dfrac{1}{4^{-2}} x^{5(-2)} y^{-11(-2)} z^{5(-2)}\bigg]$

Simplify,

$\sf \longrightarrow 4^2x^{-10}y^{22} z^{-10}$

Finally using the fourth law mentioned above , we have ,

$\sf \longrightarrow \boxed{\bf \dfrac{16 y^{22}}{x^{10}z^{10}}}$

<h3>Option K is the correct answer.</h3>

4 0

2 years ago