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Ivan
3 years ago
9

What is the slope of (-6,8) and (-6,2)

Mathematics
2 answers:
MrRissso [65]3 years ago
6 0

Answer:

Undefined

Step-by-step explanation:

The formula for slope is y1-y2/x1-x2

This is where:  

y1 is the y coordinate of the first point

y2 is the y coordinate of the second point

x1 is the x coordinate of the first point

x2 is the x coordinte of the second point

Keep in mind, a point is always (x coordinate, y coordinate)

This said we can plug our values in.

8-2/-6-(-6)

Now, we simplify.

6/0

Since you can't divide a number by 0, the slope of the line would be undefined.

This happens when a line is vertical, and only goes through one x value.

SpyIntel [72]3 years ago
4 0

Answer:

Undefined

Step-by-step explanation:

First, slope is change in y over change in x, or rise over run. Plugging these points in (y1-y2)/(x1-x2)=(2-8)/(-6--6), or -6/0. Oh no! You can't divide by 0. Therefore, the slope is undefined.

You can also see this by graphing the line, which is a straight vertical line. Vertical lines have undefined slopes.

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Which of the following is equal to the expression listed below? 25 + 10
Molodets [167]

Answer:35

Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
1. Solve the system by using a table. 3y=4x+7 , -4x-4y=28. These are the possible solutions: A) (–4, –3), B) (–3, –4), C) (4, 3)
melisa1 [442]
<span>The first question:
3y=4x+7            (1)
-4x-4y=28          (2)

Let's plug in x = -4, -3, 3, and 4 and see the y-values :)

I have attached the table since it's hard to make a table with text :P
As you can see, when x = -4, that is when the y-values are equal. That means that is the solution to the system of equations. Your answer is A) (-4, -3).

The second question:
</span><span>-3x-y=-10    (1)
4x-4y=8       (2)
</span>
When you graph both equations, you will see that they intersect at D) (3, 1).

The third question:
We need to find the lines for revenues and expenses. 
To find the line for revenues, make months the x-value and revenues the y-values. And find the equation. You should get y = 4,100x + 300.
To find the line for expenses, make months the x-value and expenses the y-values. And find the equation. You should get y = 1,900x + 19,990.

Now graph both solutions and see where they intersect. They intersect at approximately (8.95, 36995)

That would be during the month of C) August.

4 0
3 years ago
Read 2 more answers
Can anyone help me? Will give Brainly + 15 pts
exis [7]

Answer:

1,333

Step-by-step explanation:

You do v times p because you need the dividend. So you multiply the quotient and divisor.

6 0
2 years ago
The difference between two numbers is 14. if 1/3 of the larger number is subtracted from the smaller number ,the result equals 1
otez555 [7]

Answer:

Step-by-step explanation:

x-y=14

x-1/3y=1/10

-y=14-x

y=-14+x

take out the factors

x-10/30y=3/30

30x-10y=3

substitute

30x-10(-14+x)=3

30x+140-10x=3-140

20x/20=-137/20

x=-6.85

y=-14+(-6.85)

y=-20.85

7 0
3 years ago
Brian invests ?1900 into a savings account. The bank gives 3.5% compound interest for the first 2 years and 4.9% thereafter. How
Scorpion4ik [409]

let's check how much is it after 2 years firstly.


\bf ~~~~~~ \textit{Compound Interest Earned Amount} \\\\ A=P\left(1+\frac{r}{n}\right)^{nt} \quad \begin{cases} A=\textit{accumulated amount}\\ P=\textit{original amount deposited}\dotfill &1900\\ r=rate\to 3.5\%\to \frac{3.5}{100}\dotfill &0.035\\ n= \begin{array}{llll} \textit{times it compounds per year}\\ \textit{yearly, thus once} \end{array}\dotfill &1\\ t=years\dotfill &2 \end{cases} \\\\\\ A=1900\left(1+\frac{0.035}{1}\right)^{1\cdot 2}\implies A=1900(1.035)^2\implies A=2035.3275


Brian invested the money for 6 years, so now let's check how much is that for the remaining 4 years.


\bf ~~~~~~ \textit{Compound Interest Earned Amount} \\\\ A=P\left(1+\frac{r}{n}\right)^{nt} \quad \begin{cases} A=\textit{accumulated amount}\\ P=\textit{original amount deposited}\dotfill &2035.3275\\ r=rate\to 4.9\%\to \frac{4.9}{100}\dotfill &0.049\\ n= \begin{array}{llll} \textit{times it compounds per year}\\ \textit{yearly, thus once} \end{array}\dotfill &1\\ t=years\dotfill &4 \end{cases}


\bf A=2035.3275\left(1+\frac{0.049}{1}\right)^{1\cdot 4}\implies A=2035.3275(1.049)^4 \\\\\\ A\approx 2464.54\implies \boxed{\stackrel{\textit{rounded up }}{A=2465}}

4 0
3 years ago
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