Given:
Shapes: Trapezoid and Triangle.
Trapezoid: Upper base = 14mm ; lower base = 18mm
Triangle: base = 18mm ; height = 12mm
Total height of the figure is 17 mm
Area of a trapezoid = (upper base + lower base)/2 * height
A = (14mm+18mm)/2 * (17mm-12mm)
A = 32mm/2 * 5mm
A = 16mm * 5mm
A = 80 mm²
Area of a triangle = (height * base) ÷ 2
A = (12mm * 18mm) ÷ 2
A = 216mm² ÷ 2
A = 108 mm²
Total area of the figure = 80 mm² + 108 mm² = 188mm²
Answer:
4xy+13x
Step-by-step explanation:
5xy+7x+6x-xy
5xy-xy=4xy
7x+6x=13x
5xy+7x+6x-xy=4xy+13x
Answer:
slope is 9
Step-by-step explanation:
use the formula y=mx+b wherein m is the slope and b is the y-intercept
to solve for m, use formula (y2-y1)/(x2-x1):
= 
(you add 5 and 9 together because negative + negative is positive)
126/14 = 9
Answer:
<h2>
Reflection across the y-axis and 1 unit shift downside.</h2>
Step-by-step explanation:
Notice that shape A is in the second quadrant and shape B is in the first quadrant. That means there was a reflection across y-axis and then the figure was shifted one unit downside.
Therefore, the transformation was reflection across the y-axis and 1 unit shift downside. Which is a rigid transformation, because the shape and size didn't change.
