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miv72 [106K]
3 years ago
15

Which postulate or theorem proves that these two triangles are congruent?

Mathematics
1 answer:
timofeeve [1]3 years ago
3 0

what was the right answer?

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angle A is a compliment of angle b and m angle b = (6-5x) degrees and m angle a =(7-2x)degrees find m angle a
Anuta_ua [19.1K]

Answer:

61

Step-by-step explanation:

A + B = 90

6 - 5x + 7 - 2x = 90

13 - 7x = 90

- 7x = 90 - 13

- 7x = 77

- x = 77 / 7

x = - 11

A: 6 - (5 * - 11) = 6 + 55 = 61

B: 7 - (2 * -11)  = 7 + 22 = 29

Together they equal 90 as they should.

7 0
4 years ago
What is the length h of the right triangle, rounded to the nearest tenth?
gavmur [86]
Sin(35)x14 =8.03007...
So answer is 8
4 0
3 years ago
Read 2 more answers
I write down three different positive whole numbers that add to 96. The sum of any two is divisible by the third.
irina1246 [14]

Simple

  • They are 64 ,0,32

Sum of all three

  • 64+0+32=96

Sum of first two

  • 64+0=64

Divide by

  • 64/32
  • 2

Yes Verified

3 0
2 years ago
A laboratory culture contains 150 bacteria. After twenty minutes, the culture contains 300 bacteria. After one hour, the culture
erma4kov [3.2K]

This type of situation applies first order type of equation.  In this case, the equation is ln( A0/A1) = kt. A is the number of bacteria cultured. A0 is equal to 150. when A1 is 300, t is 20 minutes. that is ln (150/300) = k *20 the other condition is represented by ln (A0/1200) = 60k. k is equal to -0.0347. hence the first order equation is equal to ln (150/A1) = -0.0347 t
7 0
4 years ago
I flip three fair coins, each with a 50-50 probability of getting heads or tails. I do not show you the results, but I tell you
forsale [732]

Answer:3/7

Step-by-step explanation:

Since a coin has a head(H) and a tail(T), if two coins are flipped, the total outcome will be 4 i.e(HH, HT, TH and TT)

If 3coins are now flipped, then we will have 8total possible outcomes. The general formula being '2^n' where n is the number of coins.

The outcomes will be matching (H,T) with (HH, HT, TH, TT) to give (HHH, HHT, HTH, HTT, THH, THT, TTH and TTT). Since at least one if the 3coins shows head, then we have 7total possible outcomes excluding TTT.

Probability that exactly two of the three coins shows head (possible outcome/total outcome)

Exactly 2heads are HHT,HTH and THH(3possible outcomes)

Total outcome is 7

P(exactly two heads) = 3/7

4 0
3 years ago
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