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qaws [65]
3 years ago
12

A geometric sequence is defined by the recursive formula t1 = 64, tn = tn - 1 2 , where n ∈N and n > 1. The sequence is

Mathematics
2 answers:
zimovet [89]3 years ago
7 0

Answer:

D)64, 128, 256, 512, 1024, 2048

Step-by-step explanation:

A geometric sequence is defined by the recursive formula t1 = 64,

t_n = t_{n - 1} \cdot 2

To get the geometric sequence , plug in the value for n=2,3,4,5....

n=2, plug in 2 for n

t_2 = t_{1} \cdot 2

t_2 = 64 \cdot 2=128

n=3, plug in 3 for n

t_3 = t_{2} \cdot 2

t_3 = 128 \cdot 2=256

n=4, plug in 4 for n

t_4 = t_{3} \cdot 2

t_4 = 256 \cdot 2=512

irakobra [83]3 years ago
4 0

Answer: The anser is C

Step-by-step explanation: I honestly have no clue but im on usa test prep and guessed but got it right so I figured i'd help someone out lol, gotta go practice

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9.00/315 is a way to solve this.
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What is -14+5k-3= simplifying​
andrew11 [14]

Answer:

5k-17

Step-by-step explanation:

-14+5k-3=5k-14-3=5k-17

8 0
3 years ago
Help please! asap!
aliya0001 [1]

Answer: 50% or 1/2

Step-by-step explanation:

number of possible combos:

1+1, 1+2, 1+3, 1+4, 1+5, 1+6

2+1, 2+2, 2+3, 2+4, 2+5, 2+6

3+1, 3+2, 3+3, 3+4, 3+5, 3+6

4+1, 4+2, 4+3, 4+4, 4+5, 4+6

5+1, 5+2, 5+3, 5+4, 5+5, 5+6

6+1, 6+2, 6+3, 6+4, 6+5, 6+6

number of even sums within combos:

1+1, 1+3, 1+5

2+2, 2+4, 2+6

3+1, 3+3, 3+5

4+2, 4+4, 4+6

5+1, 5+3, 5+5

6+2, 6+4, 6+6

<u>TOTAL combos:</u>

36

<u>TOTAL even sums:</u>

18

so that means 18/36 or 1/2 of the possible combinations has a sum of an even number.

sorry it’s not a table but I literally worked it out while answering so that’s all my work

8 0
3 years ago
Solving 2 and 3 steps equations
mojhsa [17]

Answer:

I need more detail............,.....

7 0
2 years ago
For what value of the constant c is the function fcontinuous on (−[infinity], [infinity])?
Arlecino [84]

Answer:

For c=\frac{1}{7} the function f(x) is continuous on (-\infty,\infty).

Step-by-step explanation:

We have the following function

f(x) = \left\{        \begin{array}{ll}            cx^2+5x & \quad x

For the function f(x) to be continuous on (-\infty,\infty) it is sufficient to have continuity at x = 6, we need to ensure that as x approaches 6, the left and right limits match, this means that

\lim_{x \to 6^{-} } f(x)=\lim_{x \to 6^{+} } f(x)=f(x),

which holds if and only if

c\left(6\right)^2+5\left(6\right)=\left(6\right)^2-c\left(6\right)\\36c+30=36-6c\\42c=6

namely if c=\frac{1}{7}.

6 0
3 years ago
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