Please help will mark brainleistHiiii
2 answers:
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Answer:
1215 minutes are the possible numbers he has used his phone in a month.
Step-by-step explanation:
He has a monthly fee of 14$ then to the least that he has been charged we need to substract the monthly fee as follows:
Monthly charged = 74,75-14
Monthly charged= 60,75$
Then he pays an additional 0,05 $/minute of use, to know the consume:
Minutes=
Minutes= 1215 possible numbers of minutes he has used his phone.
Answer:
0.1662 = 16.62% probability that exactly 2 will stay with the same company for more than five years
Step-by-step explanation:
For each graduate, there are only two possible outcomes. Either they stay for the same company for more than five years, or they do not. Graduates are independent. This means that we use the binomial probability distribution to solve this question.
Binomial probability distribution
The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.
In which is the number of different combinations of x objects from a set of n elements, given by the following formula.
And p is the probability of X happening.
Eight percent of all college graduates hired by companies stay with the same company for more than five years.
This means that
Sample of 11 college graduates:
This means that
The probability, rounded to four decimal places, that in a random sample of 11 such college graduates hired recently by companies, exactly 2 will stay with the same company for more than five years is: the absolute tolerance is +-0.0001
The tolerance means that the answer is rounded to four decimal places.
The probability is P(X = 2). So
0.1662 = 16.62% probability that exactly 2 will stay with the same company for more than five years
<h2>Answer:</h2><h3>False</h3><h2>Step-by-step explanation:</h2>
In this problem, we have the following System of Three Equations in Three Variables, so our goal is to determine whether is the solution to this system, that is, the ordered triple
where three planes intersect.
The easier way to find the answer is to plug in the x, y and z values in the equations and figure out whether the equations satisfy the solutions. Then:
STOP HERE! Since the x, y an z values doesn't satisfy the second equation, the is not the solution to the system of equations.