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Kipish [7]
3 years ago
5

A farmer grows two types of grain in his fields. He has a seed budget of $17,000.00 and has spent $9,200.00 to plant wheat seed

so far. If barley seed costs $41.00 per acre to plant, what is the maximum number of acres of barley the farmer can plant and still be under budget?
Mathematics
1 answer:
Zarrin [17]3 years ago
7 0
Okay so first you have to subtract 17000 from 9200 to see how much money you have left to spend. Then once you get that number, which is 7800, you have to see what's that maximum number of acres that you can get. So you divide 7800 from 41.00 and you can get your answer. Your answer will be 190 acres. 190 acres is the highest you can go without going over budget.
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3/4

Step-by-step explanation:

With regards to the above, since 1/4 of the volunteers are teenagers, the fraction of the volunteers would be

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Step-by-step explanation:

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What is the range of the function f(x) = 3x2 + 6x – 8?
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3 0
3 years ago
Read 2 more answers
the length of a rectangular garden is 3 m greater than the width. The area of the garden is 70m squared. find the dimensions of
Lerok [7]
A = l x w

so you know that the length is 3m longer than the width, so you could use a formula to represent that

w = l + 3

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you could then rearrange the formula and solve for l using the quadratic formula 

0 = l^2 + 3l - 70

l = -3 +- (square root (3)^2 - 4(1)(70)) / 2(1)
l = -3 +- (square root 9 + 280) / 2
l = -3 +- (square root 289) / 2
l = -3 +- 17 / 2

then you solve for the two seperate roots

l = -3 + 17 /2
l = 14 / 2
l = 7

or 

l = -3 - 17 / 2
l = -20 / 2
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since a length cannot be negative, this root is not viable. therefore l = 7

to solve for w you would use

w = l + 3
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hope this helps! if you did not understand a step or concept please let me know!
4 0
3 years ago
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