If a1 is the first term of an arithmetic sequence and d is the common difference, then the formula for finding thenthtermofthesequenceisan =a1+(n−1)d.
Wehavebeengivena1 =5andd=15. We’reaskedtofindn=40.
an =a1 +(n−1)d a40 = 5+(40−1)·15
= 5+39·15 = 590
The 40th term of this sequence is 590.
Answer:
4x+2
Step-by-step explanation:
(13x+x−53x)−(−43x+2)
Group all the same variables on each side.
(-39x)-(-43x+2)
-39x+43x+2
4x+2
Hope this helps :)
Answer:
5x+4
Step-by-step explanation:
4x+3x+4-2x
Combine like terms
4x+3x-2x +4
5x +4
Answer:
x = 32
Step-by-step explanation:
∠BCA = ∠DBA (90 - ∠DBC)
∠A = ∠A
ΔABD similar to ΔACB
AC/AB = AB/AD
x / 8 = 8 / 2
x = 32