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Kipish [7]
3 years ago
5

A farmer grows two types of grain in his fields. He has a seed budget of $17,000.00 and has spent $9,200.00 to plant wheat seed

so far. If barley seed costs $41.00 per acre to plant, what is the maximum number of acres of barley the farmer can plant and still be under budget?
Mathematics
1 answer:
Zarrin [17]3 years ago
7 0
Okay so first you have to subtract 17000 from 9200 to see how much money you have left to spend. Then once you get that number, which is 7800, you have to see what's that maximum number of acres that you can get. So you divide 7800 from 41.00 and you can get your answer. Your answer will be 190 acres. 190 acres is the highest you can go without going over budget.
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3 0
3 years ago
Janko measures 162 cm and his father 180 cm.The father is abaut % higher than Janko​
Vesnalui [34]

Answer:

10%

Step-by-step explanation:

180-162=18

180/18=10

=10%

3 0
3 years ago
The mean age of Lincoln's tee-ball team is 5. Suppose one of his 7-year-old teammates quits the team, but a 6-year-old joins the
aleksandrvk [35]

Answer:

Depending on the amount of children in the tee ball team, the mean may be lowered drastically or minorly. However, the mean would no longer be 5, although it may round up to five, if it is a decimal.

Step-by-step explanation:

Hope that helps, I didn’t do a very good job of explaining that question. But the answer is no.

6 0
3 years ago
Read 2 more answers
What is the potential energy of a 20-kg rock perched at the top of a cliff with a height of 100 meters? O A. 2,000 J B. 19,600 J
Maurinko [17]

The Potential Energy, is given by:

PE=m\times g\times h

where:

m = mass of the object (in Kg)

g = gravity

h = height (in m)

Hence:

PE=20\times9.8\times100=19,600

ANSWER

B. 19,600 J

4 0
1 year ago
In a shipment of 20 packages, 7 packages are damaged. The packages are randomly inspected, one at a time, without replacement, u
horsena [70]

Answer:

      \large\boxed{\large\boxed{0.119}}

Explanation:

You need to find the probability that exactly three of the first 11 inspected packages are damaged and the fourth is damaged too.

<u>1. Start with the first 11 inspected packages:</u>

a) The number of combinations in which 11 packages can be taken from the 20 available packages is given by the combinatory formula:

     C(m,n)=\dfrac{m!}{m!(m-n)!}

      C(20,11)=\dfrac{20!}{11!\cdot(20-11)!}

b) The number of combinations in which 3 damaged packages can be chossen from 7 damaged packages is:

      C(7,3)=\dfrac{7!}{3!\cdot(7-3)!}

c) The number of cominations in which 8 good packages can be choosen from 13 good pacakes is:

      C(13,8)=\dfrac{13!}{8!\cdot(13-8)!}

d) The number of cominations in which 3 damaged packages and 8 good packages are chosen in the first 11 selections is:

         C(7,3)\times C(13,8)

e) The probability is the number of favorable outcomes divided by the number of possible outcomes, then that is:

        \dfrac{C(7,3)\times C(13,8)}{C(20,11)}

Subsituting:

             \dfrac{\dfrac{7!}{3!\cdot(7-3)!}\times \dfrac{13!}{8!\cdot(13-8)!}}{\dfrac{20!}{11!\cdot(20-11)!}}

             =\dfrac{\dfrac{7!}{3!\cdot 4!}\times \dfrac{13!}{8!\cdot 5!}}{\dfrac{20!}{11!\cdot 9!}}=0.26818885

<u>2. The 12th package</u>

The probability 12th package is damaged too is 7 - 3 = 4, out of 20 - 11 = 9:

<u>3. Finally</u>

The probability that exactly 12 packages are inspected to find exactly 4 damaged packages is the product of the two calculated probabilities:

         0.26818885\times 4/9=0.119

6 0
3 years ago
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