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yaroslaw [1]
2 years ago
11

Factor 30b2 + 48b - 24

Mathematics
1 answer:
iogann1982 [59]2 years ago
6 0
IM going to assume that the "2" is to be squared. If so, then the answer is 2(15x^2+8)
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The Food and Drug Administration (FDA) produces a quarterly report called Total Diet Study. The FDA’s report covers more than 20
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Using the normal approximation to the binomial, it is found that:

  • The mean of X is of 52 samples.
  • The standard deviation of X is of 4.2661 samples.
  • 0.0017 = 0.17% probability that less than half without any traces of pesticide.

--------------------------------

Binomial probability distribution

Probability of exactly x successes on n repeated trials, with p probability.

Can be approximated to a normal distribution, with mean given by:  

E(X) = np

And standard deviation of:

\sqrt{V(X)} = \sqrt{np(1-p)}

Normal probability distribution  

Z-score formula is used, which, in a set with mean \mu and standard deviation \sigma, the z-score of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

  • Each z-score has an associated p-value, which measures the percentile of measure X.

--------------------------------

  • 65% of samples had no pesticide, thus p = 0.65
  • 80 samples, thus n = 80

The mean of X is of:

E(X) = np = 0.65(80) = 52

The standard deviation of X is of:

\sqrt{V(X)} = \sqrt{np(1-p)} = \sqrt{80(0.65)(0.35)} = 4.2661

Using the approximation and continuity correction, the probability is P(X < 40 - 0.5) = P(X < 39.5), which is the p-value of Z when X = 39.5. Thus:

Z = \frac{X - \mu}{\sigma}

Z = \frac{39.5 - 52}{4.2661}

Z = -2.93

Z = -2.93 has a p-value of 0.0017, thus:

0.0017 = 0.17% probability that less than half without any traces of pesticide.

A similar problem is given at brainly.com/question/24261244

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