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3 years ago

Find the slope of the line graphed. I NEED HELP PLEASE AND THANK YOU!

Mathematics

2 answers:

Tresset [83]3 years ago

6 0

Answer:

-3/5

Step-by-step explanation:

count the rise and the run of both points

Rama09 [41]3 years ago

6 0

The answer is -3/5 to find it place your finger at the bottom red circle then count up 3 and then go to your left 5. It is a negative slope

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20 points!!!! please help fast!!!!

Lady_Fox [76]

Answer:

0 m/s

Step-by-step explanation:

The line is flat so there is no movement

7 0

3 years ago

Read 2 more answers

It takes 26 pounds of seed to completely plant a 4-acre field.

lawyer [7]

Answer:

0.153846154

Step-by-step explanation:

26 pounds for 4 acres

1 pound will need less acres

6 0

3 years ago

Which of the following best describes the equation below?

xxTIMURxx [149]

The answer is D. Linear equation

4 0

3 years ago

Read 2 more answers

I need help with this.. Anybodyyy??!

Marta_Voda [28]

Step-by-step explanation:

Given

c² = a² + b²

Making a² subject then

a² = c² - b²

Hope it will help :)

4 0

3 years ago

Find the flux of F = x^3 i + y^3 j + z^3k through the closed surface bounding the solid region x^2 + y^2 ≤ 4, 0 ≤ z ≤ 4

givi [52]

Use the divergence theorem. Let $R$ be the cylindrical region, then

$\displaystyle\iint_{\partial R}\mathbf F\cdot\mathbf n\,\mathrm dS=\iiint_R\nabla\cdot\mathbf F\,\mathrm dV$

(where $\mathbf n$ denotes the unit normal vector to $\partial R$ , but we don't need to worry about it now)

We have

$\mathrm{div }\mathbf F=(\nabla\cdot\mathbf F)(x,y,z)=\dfrac{\partial\mathbf F}{\partial x}+\dfrac{\partial\mathbf F}{\partial y}+\dfrac{\partial\mathbf F}{\partial z}$
$\nabla\cdot\mathbf F=3x^2+3y^2+3z^2$

For the solid $R$ with boundary $\partial R$ , we can set up the following volume integral in cylindrical coordinates for ease:

$\displaystyle3\iiint_R(x^2+y^2+z^2)\,\mathrm dV=3\int_{z=0}^{z=4}\int_{\theta=0}^{\theta=2\pi}\int_{r=0}^{r=2}(r^2+z^2)r\,\mathrm dr\,\mathrm d\theta\,\mathrm dz$
$=\displaystyle6\pi\int_{z=0}^{z=4}\int_{r=0}^{r=2}(r^3+rz^2)\,\mathrm dr\,\mathrm dz$
$=\displaystyle12\pi\int_{z=0}^{z=4}(2+z^2)\,\mathrm dz$
$=352\pi$

5 0

3 years ago