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3 years ago

3x + 3y =15 and x = -3y -1

Mathematics

1 answer:

saul85 [17]3 years ago

4 0

Answer:

(x, y) = (8, -3)

Step-by-step explanation:

You can substitute for x in the first equation:

3(-3y -1) +3y = 15

-6y = 18 . . . . . add 3 and simplify

y = -3 . . . . . . . divide by -6

x = -3(-3) -1 = 8 . . . . find x using the second equation

The solution to this system of equations is (x, y) = (8, -3).

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2 years ago

Lydia graphed ΔXYZ at the coordinates X (0, −4), Y (2, −3), and Z (2, −6). She thinks ΔXYZ is a right triangle. Is Lydia's asser

katrin [286]

Answer:

Option (4)

Step-by-step explanation:

Vertices of the triangle are X(0, -4), Y(2, -3) and Z(2, -6).

Slope of XY ( $m_{1}$ ) = $\frac{y-y'}{x-x'}$

= $\frac{-3+4}{2-0}$

( $m_{1}$ ) = $\frac{1}{2}$

Similarly, slope of XZ ( $m_{2}$ ) = $\frac{-6+4}{2-0}$

( $m_{2}$ ) = (-1)

$m_{1}\times m_{2}=-\frac{1}{2}$

Which should be (-1) if XY and XZ are perpendicular to each other.

Now we can say that XY and XZ are not perpendicular.

Therefore, Lydia's assertion that ΔXYZ is a right triangle is not correct.

Option (4) will be the answer.

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3 years ago

Can someone help me with 2) and 3)

zzz [600]

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2 years ago

Read 2 more answers

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3 years ago

The graph of this quadratic function is a parabola. What is the x-coordinate of the vertex? y = x^2 - 3

Studentka2010 [4]

$\bf y = x^2 - 3\implies y=1x^2+0x-3\qquad now
\\\\\\
\textit{vertex of a parabola}\\ \\
\begin{array}{llccll}
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&\uparrow &\uparrow &\uparrow \\
&a&b&c
\end{array}\qquad 
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so, the x-coordinate is $\bf -\cfrac{{{ b}}}{2{{ a}}}$

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3 years ago